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  2. ! Moderator Note You were told to do this kind of blogging elsewhere
  3. So the pin is a ball, and not a pin. Do I really need to point out that nobody can read your mind?
  4. Introduction to Schrodinger Ensemble Theory Some years ago, I chose to pursue a different approach to the study of the time-independent Schrodinger equation, particularly as it is commonly applied to the following situations: a particle in an infinite potential well, a particle in a finite potential well, the harmonic oscillator, the hydrogen atom. The first group of examples I will discuss are all one-dimensional. The work will generalize when I deal with the hydrogen atom. My concept is simple. For a given potential V(x), suppose \(\psi(x)\) is the solution to the Schrodinger equation in the form: \( (E)(\psi) = ((h/2(\pi))^2/2m)(d^2(\psi)/dx^2) + (V)(\psi) \). Suppose further that an ensemble of identical, non-interacting particles is distributed in real space at time t=0 such that the fraction of particles in the region (x, x + dx) is given by \( \psi\psi*dx \). Suppose, in addition, that these particles exhibit an initial momentum distribution such that the fraction of particles with momentum in the range (p, p + dp) is given by \( \phi\phi*dp \), where \( \phi(p) \) and \( \psi(x) \) are Fourier transforms of each other according to the usual rules. I then require that the fractional density functions be consistent across the two spaces - real space and momentum space. That is, I insist that the fraction of ensemble particles initially positioned in the region (x, x + dx) equals the fraction of ensemble particles with initial values of momentum in the region (p, p + dp). That is, I require that my consistency relationship \( \psi(x)\psi(x)*dx = \phi(p)\phi(p)*dp \) is satisfied. Finally, I use this consistency relationship to seek a momentum function p(x). On the one hand, it may be possible to find p(x) by inspection or via trial and error. Otherwise, it might be possible to integrate each side of the relationship separately and isolate p(x) from the result. Even then, there will still be some freedom left to decide on the direction of the momentum vectors. Please note that for these Schrodinger ensembles, total particle energy is not a "sharp" variable. The expectation energy averaged across the entire ensemble remains the eigenvalue E, but the energy of any individual particle is always computed from \( p(x)^2/2m + V(x) \) in the usual manner. Also note that since psi(x) and phi(p) only represent initial conditions placed on the ensemble, the subsequent development of the ensemble over time is determined by applying Liouville's theorem to the ensemble. I have not found a way to develop Schrodinger Ensemble Theory for the time-dependent Schrodinger Equation.
  5. Yes there are some conflicting results. A few studies from Italy and China indicate no difference in the load between asymptomatic and severe patients, for example. Another one suggests that the load is only different in swabs. Also animal studies with other coronaviruses suggest worse outcome with higher loads. As with anything, the knowledge is very much in flux.
  6. Today
  7. ! Moderator Note 1. This is a science forum, so that is never a valid argument. 2. Turn down the attitude or you will be taking another break.
  8. On the subject of dose, I saw this recent paper that suggests the severity of the outcome may be tied to initial viral load:
  9. If plastics are your target of choice, most EMR, from visible light ,through x-rays, to gamma radiation will degrade plastics in the following manner... Discolor or yellowing effect Change in mechanical properties (varies by material) Crosslinking – increased tensile strength, decreased elongation Chain scission – reduced tensile strength and elongation from https://omnexus.specialchem.com/polymer-properties/properties/gamma-radiation-resistance In addition to the tracks made by beta radiation ( mentioned by Swansont ), this should give you the means to discern between the three types of radiation.
  10. I know that the main problem that coused by corona diseas is Pneumonia So it may away to help the critical sick people by oxidizing there blood with Dialysis machine technology
  11. AFAIK the minimal infectious dose for SARS-Cov2 has not been established yet. I.e. no one knows yet.
  12. Why is the question "How many virus(es) - -corona , etc -- does it take cause infection" so across-the-board with responses? https://www.quora.com/How-many-individual-virus-are-needed-to-start-an-infection-Will-1-flu-virus-be-enough-to-make-you-sick-or-do-you-need-many-more-than-that
  13. Sort of... https://en.wikipedia.org/wiki/Solid-state_nuclear_track_detector
  14. This response alone would be enough to put you on most people's ignore list. But thank you for your response (2) which told me something I didn't know. Butthe Wiki article did not explicitly state there are more viruses in the ocean than not, just that there are a lot of them in the ocean. Since many human viruses are carried in the bloodstream, I am not suprised to find there are viruses in the ocean. Have a nice day.
  15. You might like to consider devising an experiment based on the response to streams of alpha, beta and gamma rays to electric/magnetic fields. http://www.passmyexams.co.uk/GCSE/physics/properties-of-radiation-magnetic-field.html
  16. It is a common observation that pathogens with long evolutionary history tend to become less virulent. Our genomes are quite full with dormant viral sequences, indicating that at some point they just became part of us. There is an assumption that there is an optimum on what level is the optimum, depending on a variety of host-pathogen factors (e.g. resistance). There has also been experimental evidence in simple systems. However, due to the nature of interact there can be cases where virulence can increase (but again, the current outbreak does show how effective tempering virulence can be). It also means that pathogens jumping hosts are often maladapted and may have suboptimal virulence (e.g. too high).
  17. It’s possible, but might require a large number of interactions to detect anything. High-energy electrons in a discharge leave tracks in plastic. They are called Lichtenberg figures.
  18. ! Moderator Note Your beliefs are irrelevant. Science is based on evidence. Support your ideas with evidence, and stop posting nonsense in mainstream threads.
  19. ! Moderator Note You were told not to bring this nonsense up again.
  20. Hello, I need some help from clever people. Regarding alpha, beta and gamma rays. If I was to shoot any of these at say a card of plastic is it possible to detect on the plastic that it had been shot with any of these? Using specialised camera perhaps? Would the rays leave a trace in any form? If not is it possible to shoot any type of rays or particles that would leave a trace on the surface of plastic at all, that Co ld be detected by a camera set up? Many thanks for all your wonderful help on this my friends.
  21. there’s more than one grey pin in these drawings. left and right are on top of each other? That’s less than intelligible. I see two pins. Which one is the “center”? One thing you could try is starting at the beginning, and disclosing all if the information, instead of jumping in at the middle and only explaining a third of what’s going on and assuming we know what you’re talking about. Now there’s a fourth ball. Where did it come from?
  22. Sorry ... no. READ THE OP. But I fully understand your typical last-word SMARTY PANTS mentality, which is TYPICAL of science and skeptic forums. But I gave you a an UPVOTE anyway b/c of your BBC link. Now where is my DOWNVOTE? Four reasons: (1) More surface area of Earth is H2O than air. And most lifeforms are in that environment. DUH!!!!!!!!!! (2) Viruses don't survive long in air, esp. under sunlight. DUH!!!!!!!!!!! (3) bacteriophages, bacteriophages, bacteriophages!! https://en.wikipedia.org/wiki/Marine_bacteriophage "Viruses have an estimated abundance of 10^30 in the ocean, or between 1 and 100,000x10^6 per millilitre." (4) Because I said so.
  23. I do not understand any of that. But do you think that what you have now is useful to you, or have you got any additional questions? Just to make sure. Once you decide on assigning some value to \(t,\) like \(\pi/6, \pi/4, \pi/3\) or any other value, then we can calculate \(\sin t\) and \(\cos t\) just in the same way that we are used to?
  24. Correct. I'm not claiming the particles are made of a mapping. I'm claiming they are the object that is mapped to.
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