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Mordred

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  1. One handy trick I learned in programming is that in binary divide and multiply by 2 is a bit shift left or bit shift right. Applying this operation can help reduce stack usage though it's been ages since I last did serious programming.
  2. At extremely low temperatures the DeBroglie wavelengths of the individual particles overlap and form a macroscopic single wavelength. Relevant formula \[\lambda_{db}=\sqrt{\frac{2\pi\hbar^2}{mK_B T}}\] As both Bose-Einstein statistics and Fermi Dirac apply the Boltzmann equation specifically Maxwell Boltzmann the mathematics will typically apply phase space. Defined by the Hamilton in the mean field approximation as a single interaction term. I have often seen this associated with the Hartree approximation to give some of the math typically involved. Should add the Compton wavelength also becomes modified into an effective Compton wavelength using the equations in the link below https://en.wikipedia.org/wiki/Gross%E2%80%93Pitaevskii_equation
  3. One detail I would like to add with regards to energy momentum. Time translations conserve energy while space translations conserve the momentum. Combining the two gives energy momentum conservation. I honestly hope you pick up on my last post orbiting bodies aren't orbiting each other. They orbit their common barycenter. With the Sun and Mercury system that's negligible that isn't true if both mass terms are similar in value. Good example Jupiter and the Sun they orbit the common barycenter just outside the Suns radius. Just a little trivial sidenot. Ever wonder how gravity wave detectors get calibrated ? They literally place a 1 ton or greater known mass beside the beam. No orbit involved yet the beam will change in angle
  4. How will that methodology work if you are given two stars of equal mass orbiting each ? How would you determine the common barycenter for other mass variations of 2 stellar objects.
  5. The method to obtain a BEC by using lasers would certainly do so. So will changing the state of the atom from one previously entangled from non BEC to BEC.
  6. Did some digging and found 3 classes of solutions all three examined in this paper. https://arxiv.org/pdf/2308.07374 With Mc Vittie being more commonly referenced (Schwartzchild FLRW metric). There are a few others but the three in this paper are seemingly examined more Anyways though there is some relevance (static vs commoving coordinate embeddings) it runs the risk of derailing the thread but thought I'd share what I found.
  7. Solid point its food for thought when I get a chance I will likely look into it in greater detail. Thanks for your opinion on an interesting problem to examine. The Desittter and anti-Desitter spacetime route may be a decent approach to the scenario to start with.
  8. That would make for an interesting superposition state. The propagation integral would also have some interesting processes. Would definitely bring new meaning to the Greens function... Lol me too
  9. I wonder if my wife would want those smart pants attached to her fit bit via an app lol.
  10. That brings to mind an interesting scenario If you go from \[R_{\mu\nu}=0\] of the Schwartzchild metric to the FLRW metric which has the time component as \[R_{00}=-\frac{3}{c^2}\frac{\ddot{a}}{a}\] With space components \[R_{ij}= (a\ddot{a}+2a^2+2c^2)\frac{g_{ij}}{a^2}\] The question of the transition distance comes to mind between the 2 scenarios. I would surmise the latter would take effect when the transition between gravitational bound spacetime regions to spacetime regions not gravitationally bound. What are your thoughts on that @KJW ? Not sure why that thought came to mind but to me it does pose an interesting question
  11. Lmao no that wouldn't be good....
  12. Im How many times has the question of mass come up this thread ? Would not distinguishing when mass becomes relevant be useful to answer those questions ? We cross posted
  13. So you believe yet you haven't actually stated any argument to counter my quoted statement. However that's a typical response I often see when I describe something that can be found in any textbook on GR. Feel free to go right on ahead on what you feel is right. I know GR is a field treatment and why it is a field treatment. Boils down to that key word distribution and a word I haven't mentioned is flow... If you want to test that try tracking 20000 test particles.
  14. No you have to think GR dont restrict yourself to the Maximally symmetric Minkowskii metric. In GR the stress energy momentum tells spacetime how to curve from the Minkowskii metric. GR describes the Field distribution of the particle ensemble not individual particle motion per se but the entire ensemble. The Minkowskii metric is what is used by SR primarily which is a specific solution of the metric tensor. \[g_{\mu\nu}=\eta_{\mu\nu}+ h_{\mu\nu}\] You likely already know the Einstein field equation so I won't waste time latexing that. In the above the \{\eta\} is the Minkowskii tensor and h is the perturbation tensor the stress tensor acts upon the permutation tensor and gives the deviations from the Minkowskii tensor to result in the new metric tensor ( can often have off diagonal terms) such as a rotating star will have off diagonal terms. However then again the Minkowskii tensor isn't always maximally symmetric take observer A rotating around observer B along the z axis \[\eta_{\mu\nu}=\begin{pmatrix}-\frac{\omega^2 r^2}{c^2}&0&\frac{\omega r^2}{c}&0\\0&1&0&0\\\frac{\omega r^2}{c}&0&r^2&0\\0&0&0&1\end{pmatrix}\] The Sagnac effect I mentioned previously here is a good stepping stone to understanding geodesics, here is a quote from the following article that applies. "From this follows that the gravitational effects are locally indistinguishable from the physical ones experienced in an accelerated frame. Such an equivalence enables us to eliminate gravity in a sufficiently small region of space-time. This is done by introducing a suitable chart which supports a locally inertial frame. One can therefore assume that freely falling, inertial frames can be defined in a sufficiently small neighborhood UP of each space-time point P, and the laws of Special Relativity, which may strictly hold only at each point P, will also be sufficiently good approximations of the true laws inside UP for all inertial observers defined therein. A typical example of such a possibility is provided by a free-falling elevator in the gravitational field of the Earth. In fact, a test body inside the falling elevator will fluctuate freely as if the elevator would be placed in empty space, in a region free from any gravitational field." The article later shows how the FLRW metric equations of state are involved in the Christoffels themself further down another relevant quote "Previously, we mentioned the Einstein’s conceptual experiment in the case of one test body inside the free-falling elevator. However, if we put two test bodies (instead of one) inside the elevator, then there is an important physical difference between the two configurations previously mentioned i.e., free-fall in a given field and real absence of field, which soon clearly emerges. Suppose, for instance, that the two bodies are initially at rest at the initial time t0. Then, for t > t0, they will keep both at rest in the absence of a real external field; on the contrary, they will start approaching each other with a relative accelerated motion if the elevator is free falling. The relative motion is unavoidable, in the second case, due to the fact that the test bodies 15 are falling along geodesic trajectories which are not parallel, but converging toward the source of the physical field. So, even if the relative velocity of the two bodies is initially vanishing, v(t0) = 0, their initial relative acceleration, a(t0), is always non-vanishing" https://amslaurea.unibo.it/id/eprint/18755/1/Raychaudhuri.pdf I invite you to study the contents in greater detail. the last should highlight the distinction between local reference frames from the global geometry So tell me I established above and you agree the mass of the test particle isn't relevent. The proper acceleration is zero and it is the field distribution of mass/energy that determines the geodesic equations of motion " the stress energy momentum tensor tells spacetime how to curve" so where am I wrong in the quoted statement that you accused me of being wrong ?
  15. incorrect the stress energy tensor tells spacetime how to curve which affects the metric tensor That stress energy tensor includes energy density and pressure terms and directly affects the metric tensor

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