Organic Chemistry

First allow me to apologize if this is the wrong place to post this query. I've been helping a buddy of mine start up his worm farm. He's working on a system of animal waste management that delivers 100% organic fertilizers and compost. My question is how do we, or rather what do we feed the worms to create 'darker' castings? We've been tinkering with the nitrogen levels, trying augments like blood meal and slaughterhouse 'fruit punch' (blood and water mixture) during the composting, but we're not there yet. Any suggestions from the Chemistry Community? Thanks. (http://www.northtexasorganics.net/)

Anyone know if reactions of this type are possible? I know organo-maganesium compounds often form nasty conglomerates. If anything prevents this reaction from working, it probably has to do with the complex Shlenck equillibrium.

A pure "Hydro-carbon" comprises a "Carbon-chain backbone", where each interstitial carbon carries 2xH, and the terminal carbons are "capped" by H: H-,C'-,C'-...-,C'-H (,C' = H-C-H) Hydro-carbons are named "number-ane" (e.g., hexane). A pure carbo-Hydrate -- what I would want to call a "Hydroxl-carbon" -- comprises the same sort of Carbon-chain backbone, but each interstitial carbon carries H+OH (and the terminal carbons are, again, "capped" by H): H-,C"-,C"...-,C"-H (,C" = H-C-OH) Hydroxl-carbons (carbo-Hydrates) are named "number-ose" (e.g., hexose), where some of the middling carbons carry 2xH, and others H+OH ?? Is there such a thing, as…

Hello! Today in the morning a friend of mine showed me his final exam in "Organic Chemistry I". He was disappointed because he had worked hard and didn't get the mark he wanted. The link of his final exam : http://multivinum.googlepages.com/home. I saw it and I think also it has few questions , it more hard than it should be, and it doesn't cover most concepts of Organic I (from easy to difficult : it seems to be mostly difficult, and many topics of "Organic I" are not covered). Can anyone pass it? (this kind of final exam). I remember a final exam of a professur from Denver, and it was for all kinds of students (and a lot of questions also). I would appreciate also a…

Hello, do you know some specific application of (E)-4-hexen-1-ol? I have already surch info. on google how to synthetise it but I didn't find what for this compound is really used. thank you

I have seen a number of Tetrahydroquinoline derivatives turning dark green from pale yellow after synthesis, as dry powders and in solvent. What it looks like on TLC: The dark green substance seems to be very polar and barely migrated. What's more, the spots in the middle of the TLC plate also turned dark green overnight. Did any possible spontaneous reaction happened to those compounds?

How do the conditions for nitration of methyl benzoate differ from those for the nitration of benzene? what is the mechanism nitration of methyl benzoate to form methyl 3-nitrobenzoate? Thanks.

I'm hoping for some help in figuring out this problem as it is a bit beyond my scope as a Microbiologist. I'm working with solvent systems and have a system that is 4.8 : 0.2 : 4 : 1 (Heptane. Ethyl Acetate: Ethanol : H20) I'm trying to figure out the percentage mass of each constituent within the solvent systems lower phase..... so it would constitute mainly the Ethyl Acetate/Ethanol/H20 Any help/ guidance would be greatly appreciated.

Can someone explain to me the precise mechanism of 1,2 cleavage by periodic acid? I understand that a cyclic periodite ester is formed, but when I count the oxygens, one seems to be missing. HO OH \ / HIO4 \ --C---C-- --------> 2x C=0 / \ H2O, THF / The periodite ester has four oxygens (two double bonded, two single) and one OH group - water must be involved, but I'm not sure how. I am assuming that in an h20 solution the periodite acid goes to IO4-, and that the H+ isn't playing a huge role. I have looked around on the net, but I haven't found anything that answers my curiosity …

If you add propane to chlorine will they react and expode without any ignition source? I believe the end result should be 1,2-dichloropropane and H2 Ive heard that chlorine and propane will explode simply when you put them together in the same container. Is this true? Or do you need to ignite them with a heat source? I also heard that even sunlight will make this mixture explode. CH3CH2CH3 + Cl2 ---> CH3CHClCH2Cl + H2

What is it? I have to do an experiment for my organic chem and I am very clueless. We are supposed to synthesize this stuff and make it react with a polyaromatic molecule to produce light. It's called chemiluminescence. Any way I have a few questions. 1) Whats a "sensitizer solution" 2) How do you prepare one? I am very new to all this sorry if this seems trivial.

Hi everyone. I have a problem and question for you. I'm working on some organic synthesis and end of the synthesis, I have undesired product which is 1,3-dichloropropanol. How can I remove this chemical. I have tried evaporation but this is not feasible because this need very much energy. If you help me, I will be pleasure

PhLi i gather is not a grignard reagent. otherwise it would be PhMgLi. I'm wondering if there is a triple bond from Ph to Li because then i will be able to use the Organo metallics with ketone reaction. Even still, i'm not sure how the valency of a phenyl ring would be able to accommodate for the aforementioned bond? The starting material is: cyclohexanone with a c=c bond on the 2nd carbon. Which leads me onto a side question, alkene's don't have prefix names and so what is the name of this molecule?Baring in mind ketone groups have a higher priority in IUPAC naming terms than alkenes. Sorry about my amateur layout. Shane btw the C=C bond is not an R group off of …

Cuando un triéster reacciona con tres equivalentes de hidróxido de sodio (NaOH), cada enlace éster se rompe por la acción del ion hidroxilo, que ataca al carbono del grupo carbonilo. Como resultado, se forman tres sales de carboxilato de sodio (que son los jabones) y glicerol como el otro producto. En el proceso, el ion hidroxilo rompe los enlaces éster, liberando el grupo alcoxi del glicerol, que luego se protona para formar el alcohol final. Después de todas las hidrólisis, los productos que se obtienen son glicerol y tres carboxilatos de sodio (R–COO⁻ Na⁺). Si la mezcla se acidifica al final, esos carboxilatos se convierten en ácidos grasos libres.

YouTube video -"1000 ways to die #316" How did he die? I did not understand the last part well. English is not my first language. is it because he smoked, that lit he's cream?

why is that chemical shift of no 1 carbon (NH2 group) is greater than no 2 carbon (NO2 group)...and no 3 carbon greater than no 4 carbon....what are the reasons.... thank you....

Hello, I am the first time confronted with a 13C-NMR, in which a coupling between the 13C and 31-P cores takes place. I am very unsure about the signal assignment in the molecule present in the appendix. I have assigned the signals so that the coupling becomes smaller at a greater distance from the 31P core. My "Assignment": 13C NMR (101 MHz, CDCl3): δ (ppm) = 232.64 (d, J = 25.2 Hz, C (14.15)), 138.32 (d, J = 40.3 Hz, C (8)), 133.07 (i.e. , J = 9.9Hz, C (9.13)), 129.59 (C (10.12)), 128.23 (d, J = 8.9Hz, 3.4)), 87.57 (C (2.5)), 80.98 (C (1)), -3.10 (C (6.7)). However, I 'm very unsure about the assignment of the 13C signals of the cyclopentadienyl ring…

Hi all, I was struggling in solving this question which is a part of practice exam , and I need you to be patient with me and teach me step by step how to figure out the structure and how to read and analyze the spectra. I attached the two 1H NMR & IR spectra so you will be able to know what structure I'm talking about. I started with finding the saturation number which is 5 so I know that at least I have aromatic ring and double bond(s) I predicted the compound to have an ester but I'm not sur. please help me to know what is this structure. The molecular formula is C8H8O2 and all the peaks and ppm readings are in the attached figures. …

2 choices but which one? Hi everyone! I recently came upon a question in an old textbook I found in school. It asked about the reacion of [ce]HBr[/ce] and [ce]C3H6[/ce]. I know the product of this reaction would be a haloalkane called bromopropane ([ce]C3H7Br[/ce]) but to my question - which would it be: 1-bromopropane or 2-bromopropane? I can find no good definate answer too this so I look to you for advice Also as a little extra why would it form that one an not the other, is there some difference in the structure that makes one more preferable than the other? Note: This is not a homework question its something I found during research and caught my …

What is the product for the following reaction? 2-bromo-3-methylbutane and HCN (This is not homework. I just want to know how the above reaction is different from NaCN which yields SN2 2-cyano-3-methylbutane.)

I would like to do some 2-D thin layer chromatography with some essential oils from several herbs. Can anyone suggest a good reference to consult regarding solvent systems? Have never tried this before so any help would be appreciated. Many thanks:)

Hi. I just did a lab where we dehydrated 2-methylcyclohexanol. We were told it would form 1-methylcyclohexene and/or 3-methylcyclohexene and we are asked to determine the major product. I figure the major product is 1-methylcyclohexene because it is the most substituted c=c. However, we are supposed to determine it using C13 NMR. We are given the "hint" to figure out how the spectra of the 1-and 3- methylcyclohexenes would differ. I don't know how to figure this out. Any suggestions?

in the reaction of 2-naphthol (structure looks like benzene + phenol)... + HCl(aq), does the OH group of 2-naphtol undergo a subsitution reaction? So.. C10H7OH(s) + HCl(aq) -> C10H7Cl(s) + H2O? Because this was a solubility test, 2-naphthol(brown looking) didn't dissolve in HCl. A cloudy solution (also brown looking) was formed. Is this a precipitate(which i'm guessing is C10H7Cl) or is it just 2-naphtol that didn't undergo the subsitution reaction?

Hey Everyone, Anyone out there have any idea on the mechanism for reacting 2,2-dimethylcyclohexanone with H2SO4 to yield 2,3-dimethylphenol. Once you protonate the ketone and form a benzene ring, how the heck is the methyl moved down to the 3 position?

Hi, I have a problem figuring out the Mechanismus for this rxn: 2-nitroresorcinol + 4-penten-1-ol --> 2-Nitro-1,3-bis(pent-4-enyloxy)benzene --> 2,6-Bis(pent-4-enyloxy)aniline Hope someone can help me with this, sumi