chenbeier

Anode is the electrode where oxidation takes place, cathode where reduction takes place. It has nothing to do with positive or negative.

The Anode is made by zinc. It has an electron pressure to get dissolved. Zink eat the OH - and release the electrons into the wire., that the reason more and more OH- will sucked there. The opposit takes place at the cathode.

That is also not right. In the electrolyte the negative charged Hydroxid ions release electrons into that electrode to be prepare to travel throw the outer circuit. So this electrode the Anode get negative charged, Oxidation takes place as described above. Zn + 2(OH)- = ZnO + H2O + 2e- The electrons travel thru the wire and the consumer resistor to the Plus electrode the cathode. Here a Reduction takes place the electrons are used to reduce that material like this equation. 2 MnO2 + H2O + 2e-==> Mn2O3 + 2(OH)- The OH- are like ferries to bring the electrons from the cathode thru the solution to the Anode.

In US Aluminum in Rest of the World Aluminium. Story here https://www.uh.edu/engines/epi1087.htm

Why not? Alkali or earth alkali sulfates can only reduced with aluminium, calcium, sodium and others.

But you have 12% , what you can dilute. Calculation shown above. By the way where do you live?

I think the moderator should close this topic now. Nothing more to say. By the way there are also receipies for elefant toothpaste by using 6% H2O2 in the net. https://www.scholastic.com/parents/kids-activities-and-printables/activities-for-kids/math-and-science-ideas/home-science-experiments-elephants-toothpaste.html

Like here https://bulkperoxide.com/

Let it be. Very dangerous, if not right Equipment and stabilizers are used. Increasing of concentration will end up with explosions. Its safer and cheaper to buy 32% H2O2 and dilute down to 24%.

The drawing on the right molecule is wrong. We have here mesomerie behaviour, the aromatic System is broken in the left Ring. https://upload.wikimedia.org/wikipedia/commons/thumb/2/27/Methylorange_Indicator.svg/480px-Methylorange_Indicator.svg.png

Yes it is

Why more confused? Na, K, Ca are innoble metals. During an electrolysis in aqueous solution these elements travel to the cathode, but instead of the element itself hydrogen will be developed from the water. Cl is an anion and travel to the Anode. Depending of the used material of the electrode, it can be developed as chlorine or it react with the electrode Material and corrodes the electrode. Alkali metal can be obtained by electrolysis of melted salt.

Sodium and a lot of other elements cannot obtained from aqueous solutions. Its a matter of the redoxpotential. Mainly elements with positiv potential can be obtained. Below 0V hydrogen will be developed. So Metal will be plated at cathode. Nonmetal will be developed at Anode. Chlorine will be developed on carbon or gold or platinum. By using of other metal, the Anode will be corode and no chlorine will be developed. Amidoximes Amidoximes such as polyacrylamidoxime can be used to capture trace amounts of uranium from sea water. In 2017 researchers announced a configuration that absorbed up to nine times as much uranyl as previous fibers without saturating. https://en.m.wikipedia.org/wiki/Oxime#Amidoximes

It is one Mg missing, it has to be Mg7Si8O22(OH)2.

It should be Mg6Si8O22(OH)2. in Comparison to Na2FeI3FeIII2Si8O22(OH)2.