chenbeier

How Keq is defined in this case?

No discussion about explosives. Read forum rules. And the method how you prepared your device shows you dont have any knowledge how colour in fireworks are created.

This method is only for hobby application. The silver deposit is poor and is more or less a immeresed reaction to copper. The adhesion is also poor seen also in the video after cleaning the coin.

I think as anormal person you cannot purchase it. Normally only companies, universities, etc. can purchase it. Somebody has to sign a document for what application it is needed. It is a very dangerous stuff. And yes it is like in movies, spies killed by them seAlso at home you dont have waste water treatment. With the cyanid you would poisson the envirement in the out going water. You need a hood and a good ventilation of course. Instead of cyanide use amin based silver salt.

How do you could measure 10 amps? Only some Milliampere is enough to split water. The voltage is also high enough. It looks like you have somewhere a interuption of the circuit.

Coppersulfate in aqueous solution is Cu(H2O)62+ + SO42-. By adding HCl a chlorido complex is formed CuCl42- and ammonia gives copper tetrammin complex Cu(NH3)42+

To make it easy C=O in the amide will be converted to CH2

In alcaline conditions also the imid group will be destroyed.

If you look from outside the electrical charges are neutral, because every H+ is neutralized by a Cl-. The reaction what is going on is solvation with the water, were H2O attract H+ to a H3O+.

Chromate only dissolved by acidic solutions or rduction compounds. NaCl alone is not able to do it.

Co(NH3)62+ => Co(NH3)63+ + e- Oxidation H2O2 + 2 e- => 2 OH- Reduktion

On safe side take a electrical fireplace.

Then you need a lot of that stuff, the business card should be wet and the guy who hand it over had to wear gloves.

Wrong. Copper is already Tetra aquo complex slight blue colour First is [Cu(H2O)4]SO4 + 2 NH3 => Cu(OH)2 + (NH4)2SO4 + 2H2O Cu(OH)2 + 4 NH3 => [Cu(NH3)4(OH)2 [Cu(NH3)4](OH)2 + (NH4)2SO4 => (Ethanol) [Cu(NH3)4]SO4 + 2 NH3 + 2 H2O

That is what I meant, it is easy to separate.