chenbeier

In alcaline conditions also the imid group will be destroyed.

If you look from outside the electrical charges are neutral, because every H+ is neutralized by a Cl-. The reaction what is going on is solvation with the water, were H2O attract H+ to a H3O+.

Chromate only dissolved by acidic solutions or rduction compounds. NaCl alone is not able to do it.

Co(NH3)62+ => Co(NH3)63+ + e- Oxidation H2O2 + 2 e- => 2 OH- Reduktion

On safe side take a electrical fireplace.

Then you need a lot of that stuff, the business card should be wet and the guy who hand it over had to wear gloves.

Wrong. Copper is already Tetra aquo complex slight blue colour First is [Cu(H2O)4]SO4 + 2 NH3 => Cu(OH)2 + (NH4)2SO4 + 2H2O Cu(OH)2 + 4 NH3 => [Cu(NH3)4(OH)2 [Cu(NH3)4](OH)2 + (NH4)2SO4 => (Ethanol) [Cu(NH3)4]SO4 + 2 NH3 + 2 H2O

That is what I meant, it is easy to separate.

A part of the solvay process it can be used to get sodium carbonate back. https://en.wikipedia.org/wiki/Solvay_process You need only some modification.

Peace people, anyway the topic should be locked by administrator. We should not discuss any topic about to make explosives.

There is no redox reaction: Ag+ + I- => AgI, This will precipitate. The ions still existing.

It react with hydrogen for example 2 H2 + ClF3 => HCl + 3 HF It is used as rocket fuel

Chlorine hexaflourid is not existing. From Chlorine there are ClF, ClF3 and ClF5 existing. All are strong oxidiser chemical like the both halogene flourine and chlorine itself.

It is the limit of your device and probably also the material of your quarz cuvette. It is in UV value.

Boil it until all water is gone. Or put it in a ball and wait some day until the water is vaporized slowly. Result you would get nice crystalls of copper chloride