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rakuenso

2-naphthol + HCL

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in the reaction of 2-naphthol (structure looks like benzene + phenol)... + HCl(aq), does the OH group of 2-naphtol undergo a subsitution reaction?

 

 

So.. C10H7OH(s) + HCl(aq) -> C10H7Cl(s) + H2O?

 

 

Because this was a solubility test, 2-naphthol(brown looking) didn't dissolve in HCl. A cloudy solution (also brown looking) was formed.

 

Is this a precipitate(which i'm guessing is C10H7Cl) or is it just 2-naphtol that didn't undergo the subsitution reaction?

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the OH group doesn't directly undergo substitution because OH- is a terrible leaving group. H2O, however, is an excellent leaving group. the OH is protonated to form ROH2+, and the Cl- displaces the H2O via nucleophilic substitution

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another question, when glucose is dissolved in HCl/NaOH/NaHCO3, does an acid and base reaction take place?

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