If the outside of a record spins faster than the inside then why doesn't the music slow down as the stylus moves inside

The record spins so slowly that the change in speed isn't that significant. However you can break a cd by spinning it really fast (not sure about the record but i'm assuming it will shatter too)

They might be varying the spacing.

 

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They might be varying the spacing.

 

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The music is recorded on to the record at the normal constant rate. The RPM is constant and the modulations of the cut will remain at the original frequencies as the stylus goes inwards because n -no matter where it is in the spiral the modulations will still be modulate at the same rate as the recording. The modulations get tighter as it moves inwards but it also moves proportionally slower, WRT to the stylus, thus keeping the original frequency reproduction. The music,naturally, gets cut onto the record at 1 second/second; compensation is not needed.

Edited May 10, 20169 yr by StringJunky

The record spins so slowly that the change in speed isn't that significant.

No. The linear speed changes quite dramatically, since it's proportional to the radial distance.

If the outside of a record spins faster than the inside then why doesn't the music slow down as the stylus moves inside

Because the outside was also moving faster than the inside when the master record was cut.

Because the outside was also moving faster than the inside when the master record was cut.

Nailed it.

Thank you all I think I understand it now

Thank you all I think I understand it now

Imagine you are sitting on a children's roundabout. You feel you are going much faster on the outside than if you sit near the centre; same with records.

Edited May 10, 20169 yr by StringJunky