  # Trurl

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• ### Sensei

1. No you are right there is no pattern in Primes in this graph. Instead it shows the value of the smaller semi-Prime. Pnp =x*y. x^3 approximate -x^3 We subtract to make x appear around y equals zero so we know where to look for it. The pattern of Primes comes from graphing all pnp’s. If you know a number is a factor of a semi-Prime you know it is Prime. I did not show that in the last graph. The last graph is to factor the semi-Prime.
2. No tricks or gimmicks. Just a way to approximate that x is 7 or below because x occurs where y =0.
3. There are 2 patterns. The one found in this graph where all possible x’s are graphed against a know pnp. And the other graphs that compare the known pnp to a calculated pnp. This graph is the first case. It is definitely logarithmic. In fact, I think it is related to the normal distribution. I show -5 to 5. Yes I know I must know x = 5 when looking at the graph. But you must admit when you plug and chug different values x, the results should be approaching x to the third. The other 3 equations in this thread still apply. They are just overly complex. The graphs of those equation
4. You are correct the equation is only true for zero for integers. But as you also know I am only looking for decimal approximations. An x of 5 and a pnp of 85 fall within reasonable range. I am looking for numbers for computation. The application of the cubed root of 124.9136 is close enough to the cubed root of 125.
5. Sorry try Remember there is no guarantee it works, but it is simple enough to test. x^3 = [(x^3 * pnp^2) / (pnp^2 + x)] try pnp=85 and an x of 5 Then test more values.
6. Just for you Ghideon I simplified the equation to prove you do understand it. It has been said if you can’t explain it simply you don’t understand it. Remember there is no guarantee it works, but it is simple enough to test. x^3 = [(x^2 * pnp^2) / (pnp^2 + x)] try pnp=85 and an x of 5 Then test more values. Again it may not work but you have followed my thread and challenged me to simplify and prove my hypothesis.
7. “Remember I am claiming I can factor semi-Primes and thus RSA cryptography would be no more.” This comment is to create interest. It is why we are finding semiprime factors in the first place. If I could factor semiprimes with the Pappy Craylar method it would break RSA cryptography. RSA is the first public key crypto. There is no longer prizes for cracking it hence the Pappy Craylar method is shared here. “Yes. And my understanding of the is that you try the opposite; predicting the person from too few polygons. Crude example: There is a pattern, all my models h
8. “I know where you claim the pattern to be. I want to know how there could be a pattern.” How could there not be a pattern? How is there a pattern in DNA with billions of proteins? It is just a model to better understand relationships. Do patterns exist or do you create them? Graphing the equation for possible x’s for given semi prime should show a pattern of x. A scatter plot may or may not show a pattern. But most things that are described by equations is a first step in finding patterns, especially when they are graphed. The graph of the logarithmic spiral is separate from the
9. Sorry for the delay. I was on a trip. Well my goal is to convince you a pattern exists. The scatter plot does not show a pattern, but that is true of many patterns. Although some one YouTube did show that Prime numbers in the coordinate plane fits a logarithmic spiral. It is different from my work but I say the 4 equations show the pattern. If you graph the equation for one Prime number and a domain of possibly x values, it is an inverted normal distribution. The pattern is in the equations. Without that pattern we have no pattern. So if you do not see a pattern in the equations
10. There is a chance my spiral may “break the rules” of a log spiral. If so it doesn’t matter it would just be a custom spiral. I need to draw it. From here on out I will call this project the Pappy Craylar Conjecture.
11. Yes a semi-Prime based on two random Primes. I refer you to the four equations already in this thread. Plug and chug. I know plug and chug is referred to as improper math, but here we are just testing values. I know I can’t yet find x perfectly. But the equations show the pattern between the semi-Prime and the smaller factor x. I know you are think so what if we know PNP and x we know y. Point taken. But you can test for x by graphing the equation. Which I am arguing is faster then recursive division. The pattern I am trying to draw on the log spiral is from the four eq
12. Awesome link. I wonder what they used to create the graphics. That is different from my attempts. They just have a sieve. I am trying to find a log spiral where the area equals the Prime products. The area should not equal with numbers that aren’t Prime. The parabola I created isn’t a sieve. That is why I asked you to look at the worked example. I tried to write a mathematical proof. I enjoyed the link. I have never seen other people relating Primes to parabolas. It seems like just a sieve and it is very complex. I know my looks complex like any factors will
13. Clarity and argument are good. I post to solve problems and have good discussion. I envisioned the log spiral to increase in magnitude. The magnitude being the arc of Prime factors, 5 and 17. I propose as the magnitude increases so does the log spiral and it’s sector. That is given. But what if we graph 3*5 then graph 5*7 then 7*11 then 11*13? Will we find relations between their angles and areas of the sector. I don’t know of any attempts to do this.But other the circular functions and a spiral I don’t know where this idea could be tested geometrically If you took 3*5 then 3*7 the
14. Well that is completely unscientific. You did not prove it wrong. You took one value and came to the conclusion it has nothing to do with Semi-Primes even though you just took 2 factors and related the sector area to the Semi-Prime. So simple that it seems insignificant. But the hypothesis exists to disprove. You have to creat an algorithm to graph all known Semi-Primes or at least enough to sample the data. If you believe that any of the 4 equations I posted show any pattern in the factoring of Semi-Primes, why would you think this geometric model would not have any truth?
15. A=r(φ2)2−r(φ1)2 /4K But you didn’t use the area equation right. Radius * angle squared - radius * angle squared divided by 4K
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