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Everything posted by Trurl

  1. Back to the discussion. I concede using triangles to relate factors to products is challenging. This is the best I could come up with: For semi-Primes and their product where 5 * 17 = 85 a logarithmic spiral with radius 5 and 17 with the angle between 5 and 17 equal to the angle where the area of the logarithmic spiral encompasses an area of 85. You just design the spiral using the known 5, 17, and 85. Do you see any advantage to doing this? I am working on a worked example. The reasons I think it is useful is that it is simple, incl
  2. I Ok. You wanted a worked example. This is for “crafting” a triangle. There is a high probability it doesn’t work. But I wrote it in 2009 and am trying to relearn my reasoning. This isn’t the “vector factors” I talked about. But it is a geometric representation of algebra. It is what is in the pdf I posted but you probably haven’t seen it. It is based in a parabola. I just want to know if it works. No one has ever tested it. I know it might appear absurd but I was inspired when I wrote it. I will address the current discussion in a future post. It is difficu
  3. I am working on a example. You are right the idea may be too abstract to be useful. I was asking you guys if there was some relation to relate geometry to factors. I believe it may be possible. It doesn't have to be overly complex. I read once that we use the coordinate plane as our main reference for a coordinate system, but we forget anything geometric can create a simple, custom coordinate system. I want to make vectors relate to factors. I know that 5 * 17 = 85 would need an angle greater than 180. But what if the magnitudes of the 5 and 17 results in the same angles as 3 and 13 only the m
  4. All my hypotheses in this thread rely on these 4 equations being true. p3 = ((pnp^2 + x^3) / pnp) – ((pnp + (x^2 / (pnp^2 + x)) * pnp)) p5 = (pnp^2 + x^3) / pnp - (x^3 / pnp) Separate equations. pnp=x*y x&y are Prime factors of semi-Prime pnp Don’t simplify, graph in software. x = Sqrt[ [ ((x^2 * pnp^4 + 2 * pnp^2 * x^5) + x^8) / pnp^4]] [pnp^4 = [[ ( (pnp^4 * x^2 + 2 * pnp^2 * x^5) )] / x^2 ] – [(x^3 / pnp / 2)] 2 separate equations. pnp = x*y pnp is the known semi-Prime and x and y are
  5. Studiot, when you recommended Mark Levi’s book did you see a parallel in that it was as confusing as my posts? I mean the guy is a mathematician and physicist so he is more skilled than me. The majority of reviews are 5 stars. But the text was not user friendly. It is...proof...diagram...proof with one or two sentences to explain. It would take me hours each proof to find out what he is talking about. And he said you only need geometry. I could take his word the proofs work, but wouldn’t that defeat the purpose? I loved the first chapter where he was going to relate pure math to p
  6. Thanks Studious. I am going to get that book. I think it will help me communicate ideas. No one knows what I am saying. The ideas might just be too abstract. I thought the 4 equations were concrete. But you are right I have to come up with something tangible. One clear example. I included a PDF in the last post you read. Is that any help? I do have the second part of my write-up. I am aware the following hypothesis most likely don’t work, but do you get any ideas when you read them? I am describing geometry. Easy enough to make a hypothesis, but I have not been successful. When you read
  7. Ok, this post has many views no comments on my new hypothesis. I do understand that it may be that no one is exactly sure what it is I am doing. I am not doing one thing in this post. The goal was to present my equations that solve for x knowing only pnp. I think we can agree that the equations are significant, but to find a practical solution we need the ability to solve large numbers. What works for 5 and 17 is easy to solve, but advanced computer programming is needed to crunch a 100-digit number. I am trying to improve my ability of explaining mathematical subjects. I just finished r
  8. Ok I’m going to bounce an idea off you. If it is total wrong it doesn’t mean it isn’t important. I began my work on Semi-Primes years ago with a vision that a logarithmic spiral could show a pattern in Prime numbers. I have heard others say this, but they were talking a scatter plot while I tried to make my spirals characteristics match the properties of the Prime numbers. And of course, it is easy to say a logarithmic spiral will show a pattern, but finding the pattern is the challenge. I attempted several attempts without success. The Hypothesis: If you draw an angle betw
  9. If you are interested in these equations visit my status page. i stink at writing for mathematics. So much for publishing a textbook. My education professors said I was writing musings for the internet. It may not seem like it but I have an undergraduate understanding of math. I enjoy reading Michio Kaku’s books. String theory is pure math. I love plugging numbers. Can anyone suggest a site with string theory math for the novice? From what I understand the math of modern physics is out of control. Anyways enjoy the link in about me page. Can anyone recommend a book about writing for
  10. https://www.amazon.com/Prime-Number-Factors-that-Solve-ebook/dp/B079XYZ596/


    Book is free May 18th through 20th.

    It is horrible, but shows why equations were formed.

  11. Good eye. x = Sqrt[ [ ((x^2 * pnp^4 + 2 * pnp^2 * x^5) + x^8) / pnp^4]]
  12. Here is my previous attempt at a perfect equation to find semi-Primes. The trouble is that it is too complex to solve easily. x = Sqrt[ [ ((x^2 * pnp^4 + 2 * pnp^2 * x^5) + x^8 / pnp^4]] [pnp^4 = [[ ( (pnp^4 * x^2 + 2 * pnp^2 * x^5) )] / x^2 ] – [(x^3 / pnp / 2)] Test these equations. If you want to know how they were derived pm me and I will send you a link to download free. I don’t mean to advertise, but if you are interested pm me. It is the easiest way to get you a lot of information.
  13. I am only kidding. I did not think of it either. My nephew said he had a friend that did math on excel and mathematics. But it didn't click because they never taught that in school. I was watching a video of The Great Courses and the instructor showed how computers solve differential equations. It is a cheap and powerful method. But it may be able to graph from 0 to pnp.
  14. One more post before I conclude this project. Why did no one recommend Excel for the graph and the list? It would graph and list an N of 100 digits easily. It has a segment of adjustable accuracy. Spread sheets are common to solve graphs and differential equations and it is a tool everyone has access to. It would take more adjustments with Mathematica. Of course if you didn’t believe in my work you wouldn’t mention this simple tool. However if you think it can be estimated with a simple graph you have already plugged it into the spreadsheet without sharing.
  15. Lock this thread. I have spent years reading encryption books and tinkering with Prime numbers. It was very valuable in that I could study statistics, game theory, review calculus and work on ideas. It was more than just crunching x’s and pnp’s. That is why I keep it up. I even learned the basics of Mathematica. My end result was to approximate x by graphing a pattern in division. I need to know what x will have a y value of N. I can’t graph it accurately enough with standard programs. I don’t know if there are any computer programs to graph a range that is pnp. I could take guess at the
  16. p3 = ((pnp^2 + x^3) / pnp) – ((pnp + (x^2 / (pnp^2 + x)) * pnp)) p5 = (pnp^2 + x^3) / pnp + (x^3 / pnp) where N = pnp for computer computation Given equations p3 and p5. p3 is equal to p5 a distance of N. Since N is the distance subtracted from p5 So, p3(x_semiPrime)=0 and p5(x_semiPrime)=N That is y=0 at an x equal to the smaller semi-Prime at p3. And at p5, y=N. Knowing the above, p3(x) = p5(x+N) so p3(N)=p5(N+N) since these equal the derivative of those should also equal p3’(x) = p5’(
  17. Both good explanations. I don’t know what to think of multiple realities. With all the histories and multiple realities, we forget we are living it. Our lives are just as significant as any reality.
  18. In Star Trek Next Generation the last episode “All Good Things,” the character Que, an omnipotent being, suggest the crew was not in space to map constellations. But all our physical sciences are based on these observations, So my question is what is Que suggesting?
  19. Ok, I hope this makes sense. It is only an idea. I just wanted to post it to see if it makes anyone else see something new in a plain graph. I had trouble finding the values on the graph of x when N is a hundred-digit number. I was certain that I could just zoom in or pan the graph to see the proper value. As I have found, this is difficult to do in practice. So I am back at just approximating x and using test values. But in trying to do this I noticed something else that would help in the search for x knowing only N. So for N = x *y, where x and y are 2 unknown Pri
  20. Ok, so I graphed the RSA 100. There is one problem in particular. I just can’t read the axis’ scale. I am researching how to evaluate the graph in Mathematica. I just need to find xongraph where yongraph equals pnp. That would be the range. I believe you can test for yongraph on a graphing calculator and find points on the graph. I post this as a mathematical challenge to the SFN community. How do I arrange the scales in mathematic software to find the y value I am looking for? It takes milliseconds to draw, but I need to be able to evaluate it.
  21. For a large N use a software like Mathematica and paste in N. Yes I know math types don’t like that. I apologize. It just needs some properties as an algorithm. So in the following Mathematica code replace pnp with N and graph and look for a yonthegraph of pnp. Work from the left side. I don’t know it’s speed compared to other methods. The truth is I don’t know the other methods. I know they rely on series. I took a simpler approach and looked for patterns in the division of semiPrimes. My question does it work for all factor, not just factors of
  22. Here is the summary of my work: The main equation is: (N^2+x^3)/N = N+[(x^2/((N^2/x)+x))*N] All the other math is the simplification of this equation. If you simplify the equation completely it results in zero equals zero. Which is not particularly useful. But we can put N the given semiprime product of x and y, where x and y are the Prime factors. As I have showed in the examples if you “plug and chug” “N” into the equation and graph the equation in its un-simplified form, then my hypothesis says that reading the graph in how I told you to read p3 and p5 should rev
  23. PNP is the variable name of the semiPrime in question. It is the given. It is usually referred to as N as in N=p*q, where p and q are the Prime number factors. PNP is my name because I cannot call it N because N is a keyword in Mathematica. PNP or N is the factor of 2 Primes and is the given in RSA cryptography. Finding x knowing only N is considered difficult with large Prime factors. The goal of this work is to use a simple mathematical pattern to list N in terms of x, than reveal the value of x in the graph of the equations. So basically, if you did not understand my write up, you coul
  24. PNP is N in this. Originally it was N = p*j. But N is protected in Mathematica so I renamed it pnp. N = p*J = x*y, because I also called p, x and j, y. This is a poor decision because when you graph it ygraph is different from y in the equation. So it created some confusion, but writing this up and coming up with a solution variables get jumbled. DLP is the discrete logarithmic problem. If this can factor semi-Primes then the DLP is next to go. Remember I am claiming I can factor semi-Primes and thus RSA cryptography would be no more. But it wouldn't matter because other cryptosystems wou
  25. I know I not the best math teacher. What parts do you not understand? I am taking the known semiPrime, PNP, and graphing it along the x axis to find the place where y equals zero. I do this to find x knowing only PNP. Look at the pdf I posted (see previous post attachment). You will see 2 equations, p3 and P5, and the graphs that correspond to them there. N=1847*2393=4419871=4.4199871*10^6. (These are N=x*y as an example) For p3 as y approaches 0, x will be 1847 or x. For p5 as x approaches 1847, y=4.4199871*10^6
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