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Sensei

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Everything posted by Sensei

  1. The most of modern C/C++ IDE's have syntax checking, wrong entered stuff is highlighted.. Visual Express/Studio is searching for names of variables, members, classes while entering couple letters, suggesting what you might want, and then you can pick it up from drop-down list. Use f.e. ConTEXT editor for programmers. It can analyze different types of languages, PHP, C/C++, JavaScript etc. http://www.contexteditor.org/ In interpreted languages the all variables are strings. So language doesn't need to know type, when there is just one type variable you can have. In C/C++ you need to tell language what will be type of variable, otherwise it doesn't know type. In C/C++ string doesn't even exist as language standard (std::string is just yet another optional to use class included in external linked library). There is array of characters (char name), which is equal to array of bytes. You can't use it as "default type", without telling how large is array, and we are back to root.. At modern times in serious programming everybody are using Unicode, which has wider character standard.
  2. I have made couple devices for fast production of Hydrogen, Oxygen and Chlorine, and NaOH (because had enough waiting for slow battery rate). Mine normal rate is 1 Liter of Hydrogen per hour easily. Couple times measured. The bigger area of electrodes, the more current is flowing. But usually people are using 60 grams of NaCl and 18 grams of H2O which has volume = ~28 cm^3, so it's hard to use large size electrodes.. But I bet, he used metal which is immediately reacting with solution. If I use steel or aluminum for positive electrode, there is often no sign of Chlorine, instead electrode is dissolving. You need/should use carbon-graphite electrode for positive electrode (or better for both). 1 A * s = 1 C 1 C / e = 1 C / 1.6*10^-19 = 6.25*10^18 electrons (in theory) one electron can split H2O to OH- and H+ So there are needed 2 electrons to produce one molecule H2 1 L of H2 has mass 0.08988 g/L 1 molecule of H2 has mass 2 * 1.0078 g/Na = 2 * 1.67*10^-24 g so in 1 L there is 0.08988 g/3.3469*10^-24 g = 2.68*10^22 molecules of H2 2.68*10^22 / 3600 seconds = 7.459*10^18 molecules produced per second *2 electrons needed to each molecule= 1.492*10^19 electrons per second needed Which is 2.387 A average. I can easily go beyond this current. Today I was using 5 A to produce Hydrogen in experiment.

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