Commander Posted January 22, 2021 Share Posted January 22, 2021 Make 44 using once each 2, 11, 13, 17, 19, 101 with only + - x / ( ) as Operators. Link to comment Share on other sites More sharing options...
Sensei Posted January 22, 2021 Share Posted January 22, 2021 I have extension to your teaser: Make 0 using once each 2, 11, 13, 17, 19, 101 with only + - x / ( ) as Operators. Spoiler (17-2)*(19-13)+11-101 = 0 Link to comment Share on other sites More sharing options...
Commander Posted January 23, 2021 Author Share Posted January 23, 2021 10 hours ago, Sensei said: I have extension to your teaser: Make 0 using once each 2, 11, 13, 17, 19, 101 with only + - x / ( ) as Operators. Reveal hidden contents (17-2)*(19-13)+11-101 = 0 Very nice. There are many other numbers possible too ! Link to comment Share on other sites More sharing options...
Sensei Posted January 23, 2021 Share Posted January 23, 2021 The answer for your initial question is: Spoiler (101-13)/(17-(11+19)/2)=44 1 Link to comment Share on other sites More sharing options...
Commander Posted January 23, 2021 Author Share Posted January 23, 2021 Well done ! The other answer as originally planned is : 2(11((13*17)-19))/101=44 Link to comment Share on other sites More sharing options...
md65536 Posted January 23, 2021 Share Posted January 23, 2021 I got (101+11+19-17)/2-13=44. 1 Link to comment Share on other sites More sharing options...
Commander Posted January 24, 2021 Author Share Posted January 24, 2021 14 hours ago, md65536 said: I got (101+11+19-17)/2-13=44. Excellent ! Perhaps getting 22 using once each 11, 13, 17, 19, 101 with only + - x / ( ) as Operators might be tougher ! I wanted to have 6 numbers and therefore added 2 ! Link to comment Share on other sites More sharing options...
Sensei Posted January 24, 2021 Share Posted January 24, 2021 10 hours ago, Commander said: Perhaps getting 22 using once each 11, 13, 17, 19, 101 with only + - x / ( ) as Operators might be tougher ! Not for me.. (((13×17)-19)×11)/101=22 Link to comment Share on other sites More sharing options...
md65536 Posted January 25, 2021 Share Posted January 25, 2021 I was curious about how many answers there might be, so I wrote code. I gave up before trying to deal with parentheses, but got the following: (11 - 17) * 13 + 2 + 19 + 101 = 44 (11 - 13) * 19 - 17 - 2 + 101 = 44 (13 + 101) / 2 - 11 - 19 + 17 = 44 (11 - 13 - 17) * 2 - 19 + 101 = 44 (13 - 17 - 19) * 2 - 11 + 101 = 44 (17 - 19 - 2) * 11 - 13 + 101 = 44 (17 - 19) * 11 * 2 - 13 + 101 = 44 (13 - 11 + 19 + 101) / 2 - 17 = 44 (11 - 17 + 19 + 101) / 2 - 13 = 44 (my answer) ((17 - 19 + 101) / 11 + 13) * 2 = 44 ((13 * 17 - 19) / 101 + 2) * 11 = 44 ((19 - 11) * 17 - 13 - 101) * 2 = 44 (13 * 17 - 19) / 101 * 2 * 11 = 44 (Commander's answer, ignoring order) Sensei's answer isn't here because it's not left-to-right order of operations. I wouldn't doubt this is a small fraction of the possible answers, but neither would I bet that it is. (I also manually culled duplicates so I may have removed too many.) Link to comment Share on other sites More sharing options...
Commander Posted January 27, 2021 Author Share Posted January 27, 2021 Let's try this new one : Make 4321 using all these numbers only once 2,3,5,7,11,13,17 with operators + - x / and Brackets. Another one : In this sentence, the number of occurrences Of the digit 0 is__? Of the digit 1 is__? Of the digit 2 is __? Of the digit 3 is __? Of the digit 4 is__? Of the digit 5 is__? Of the digit 6 is __ ? Of the digit 7 is __? Of the digit 8 is__? Of the digit 9 is __? Please fill in the blanks. Make the sentence valid ! Link to comment Share on other sites More sharing options...
John Cuthber Posted January 27, 2021 Share Posted January 27, 2021 2 hours ago, Commander said: Let's try this new one : Make 4321 using all these numbers only once 2,3,5,7,11,13,17 with operators + - x / and Brackets. Another one : In this sentence, the number of occurrences Of the digit 0 is__? Of the digit 1 is__? Of the digit 2 is __? Of the digit 3 is __? Of the digit 4 is__? Of the digit 5 is__? Of the digit 6 is __ ? Of the digit 7 is __? Of the digit 8 is__? Of the digit 9 is __? Please fill in the blanks. Make the sentence valid ! There are several options. Replace all the blanks with "one". Replace all the blanks with ">=1" Replace all the blanks with "unimportant". Replace all the blanks with "less than 99" Link to comment Share on other sites More sharing options...
Commander Posted January 28, 2021 Author Share Posted January 28, 2021 (edited) On 1/27/2021 at 5:39 PM, John Cuthber said: There are several options. Replace all the blanks with "one". Replace all the blanks with ">=1" Replace all the blanks with "unimportant". Replace all the blanks with "less than 99" Hi, Only positive numbers to be used to fill in the blanks. Also no leading zero too such as 02 etc Edited January 28, 2021 by Commander Link to comment Share on other sites More sharing options...
Sensei Posted January 28, 2021 Share Posted January 28, 2021 (edited) On 1/27/2021 at 11:03 AM, Commander said: In this sentence, the number of occurrences Of the digit 0 is__? Of the digit 1 is__? Of the digit 2 is __? Of the digit 3 is __? Of the digit 4 is__? Of the digit 5 is__? Of the digit 6 is __ ? Of the digit 7 is __? Of the digit 8 is__? Of the digit 9 is __? Please fill in the blanks. Make the sentence valid ! Some irrational numbers e.g. PI have infinite number of digits of each kind in decimal numerical system. Edited January 28, 2021 by Sensei Link to comment Share on other sites More sharing options...
Commander Posted January 29, 2021 Author Share Posted January 29, 2021 On 1/24/2021 at 11:52 PM, Sensei said: Not for me.. Reveal hidden contents (((13×17)-19)×11)/101=22 Good ! 13 hours ago, Sensei said: Some irrational numbers e.g. PI have infinite number of digits of each kind in decimal numerical system. No irrational Numbers. Simple Positive Integers. There are 2 Solutions known. You need to find both ! Link to comment Share on other sites More sharing options...
John Cuthber Posted January 29, 2021 Share Posted January 29, 2021 13 hours ago, Sensei said: Some irrational numbers e.g. PI have infinite number of digits Then they are unlikely to be in that sentence. Link to comment Share on other sites More sharing options...
md65536 Posted January 29, 2021 Share Posted January 29, 2021 8 hours ago, Commander said: There are 2 Solutions known. You need to find both ! It's a bit confusing because it's not a valid sentence with all of those question marks, but if they're changed to commas, one solution is Spoiler 1, 11, 2, 1, 1, 1, 1, 1, 1, 1 Is this the easier solution? Oh I see, just by trying some things out: Spoiler 1, 7, 3, 2, 1, 1, 1, 2, 1, 1 1 Link to comment Share on other sites More sharing options...
Commander Posted January 30, 2021 Author Share Posted January 30, 2021 (edited) 12 hours ago, md65536 said: It's a bit confusing because it's not a valid sentence with all of those question marks, but if they're changed to commas, one solution is Reveal hidden contents 1, 11, 2, 1, 1, 1, 1, 1, 1, 1 Is this the easier solution? Oh I see, just by trying some things out: Reveal hidden contents 1, 7, 3, 2, 1, 1, 1, 2, 1, 1 Absolutely Right ! Well done ! Yes, the first solution is easier and the second is harder ! 2 + to you ! If I could give. Yes the Question marks can be removed. Edited January 30, 2021 by Commander Link to comment Share on other sites More sharing options...
Commander Posted February 1, 2021 Author Share Posted February 1, 2021 The following is still to be solved : Make 4321 using all these numbers only once 2,3,5,7,11,13,17 with operators + - x / and Brackets. Link to comment Share on other sites More sharing options...
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