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Testing latex


John2020
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  • 2 weeks later...

Testing relativity formulas for the thread which name we do not mention...

\[ t = \frac{{t}' + \frac{v{x}'}{c^{2}}}{\sqrt{1 - \frac{v^{2}}{c^{2}}}} \]

 

\[t = \frac{{0} + {0.8} . {0.6} }{\sqrt{1 - {0.8 ^{2}}}}\]

Edited by Eise
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  • 5 months later...

Testing more stuff.

\[ f\left(x\right)=\begin{cases} 1, & x\in\mathbb{Q}\\ -1, & x\in\mathbb{R}-\mathbb{Q} \end{cases} \]

Testing more stuff.

\[ \textrm{int}C\neq\textrm{Ø}\Rightarrow\textrm{if }x\in C\Rightarrow\in B_{\epsilon}\left(x\right)\subseteq C\Rightarrow\mu\left(C\right)\geq\mu\left(B_{\epsilon}\left(x\right)\right)>0 \]

 

 
Edited by joigus
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Rather:

\[ \textrm{int}C\neq\textrm{Ø}\Rightarrow\textrm{if }x\in C\Rightarrow B_{\epsilon}\left(x\right)\subseteq C\Rightarrow\mu\left(C\right)\geq\mu\left(B_{\epsilon}\left(x\right)\right)>0 \]

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  • 1 month later...
Posted (edited)

Total energy:

\[E=\frac{mc^{2}}{\sqrt{1-v^{2}/c^{2}}}\]

Rest energy:

\[E_{0}=mc^{2}\]

Kinetic energy:

\[\textrm{K.E.}=\frac{mc^{2}}{\sqrt{1-v^{2}/c^{2}}}-mc^{2}\]

Edited by joigus
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  • 5 weeks later...
Posted (edited)

[math]\begin{align} \text{text} \end{align}[/math]

[math]\color{blue}{\text{text}}[/math]

text

[math]F = ma[/math]

 

 

 

Edited by Orion1
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Posted (edited)

\[\int (f(x)+ dy/2)dx= \int f(x)dx+ \frac{1}{2}\int dydx\]

\[ \frac{1}{2}\int dydx \]

 

Inline: \( dy\left( x \right) = y'\left( x \right) dx \).

Edited by joigus
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Posted (edited)
17 hours ago, joigus said:

 

(f(x)+dy/2)dx=f(x)dx+12dydx

 

 

12dydx

 

 

Inline: dy(x)=y(x)dx .

@joigus, how did you center your equations?

I cannot get \begin{center} command to work.

 

 

Edited by Orion1
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1 hour ago, Orion1 said:

@joigus, how did you center your equations?

I cannot get \begin{center} command to work.

 

 

I just use \[ (and the closing square brace) for centred (display) equations and \( (and its closing round brace) for inline maths. It seems to interact well with the MathJax "engine".

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