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Everything posted by joigus

  1. Very well explained here: https://en.wikipedia.org/wiki/Innumeracy_(book)
  2. The more I think about superdeterminism, the more I think it's possible and, as Hanke said, untestable. Is it possible that back in a remote past of a preinflationary period lies the key to every happenstance in the universe? It's possible. It's a matter of plausibility perhaps. Occam's razor is sharp indeed. One should be, shouldn't one?
  3. Aaah. I'm a stickler for precise terms. As if that was the problem with the present crossroads we're in. It's probably not. Revealed does have a religious sound to it though...
  4. Ok. For the record, I think you're right that Genady's metric just describes flat spacetime, and that this argument that I'm giving is really clutching at straws. I was exposed to Schwarz's/Clairaut/Young theorem in the past and I remembered that if a function is not C2 (never mind the only non-continuous derivatives being the diagonal ones) the conditions of the theorem are no longer satisfied and it could happen that some devilish argument gives you a contradiction. I just don't know. Thereby my question "are you sure?" which I should have formulated more clearly. My intuition tells me that fxy and fyx could give you problems, but fxx and fxx is the same thing no matter what the continuity status is, because x is the same thing as x, as you rightly imply. Another part that makes me think that you're right even from the POV of a rigorous proof is that the distributions involved are Heaviside's, the delta, and its derivative. And those are extraordinarily well-behaved as long as you never integrate them against functions that don't fall to zero fast enough at infinity. All functions we use in physics fall to zero pretty fast, so no problem there. As to your question for me, if by "pathological" you mean "not continuous", it's not possible to have a composition of two functions, one continuous, and the other not, that gives you a continuous function. So my answer would be no. What does happen sometimes is that, trying to solve EFE, we get bad coordinate systems, and we must use singular coordinate transformations that mend the "singularities" that were never there in the first place. I do know that that's what happens with the Kruskal-Szekeres coordinates. After all, the composition of two singular transformations can restore continuity, exactly as 1/u (singular at u=0) with u=1/x (singular at x=0) becomes just x (continuous everywhere). It indeed is.
  5. Oh, believe me, I did. One would think it's you who doesn't want to grasp the logic behind mine: Are you sure? Symmetry of partial derivatives is a consequence of continuity: https://en.wikipedia.org/wiki/Symmetry_of_second_derivatives#Schwarz's_theorem Somewhere on the back of my mind I was trying to remember an argument that validates it. It might be something like this: https://en.wikipedia.org/wiki/Symmetry_of_second_derivatives#Distribution_theory_formulation But this is becoming farther and farther away from the OP with every post --and less and less interesting for everybody else, I suspect. Mm... Yes, you're right. Genady actually said it (if I understood correctly). That, as \( G_{\mu\nu}=8\pi G T_{\mu \nu} \), any \( G_{\mu \nu} \) obtained from the metric connection by means of the \( g_{\mu\nu} \) you give yourself can be used as the \( T_{\mu \nu} \) just after dividing by \( 8 \pi G \).
  6. I hereby propose Godwin's second law. Namely:
  7. Yes, it's flat space-time, almost everywhere. It seems obvious, doesn't it? A simple re-scaling of the variables takes you back to Minkowski. When I said "are you sure?" I meant that all the derivatives cancel. That there is total continuity. That "there is no problem", as you implied. This requires a calculation, and perhaps a little thought too. I'm getting, \[ g''_{zz}\left(z\right)=2H\left(z\right)+2z\delta\left(z\right)+12z²H\left(-z\right)-12z³\delta\left(-z\right) \] This is discontinuous because of the step function, not because of the delta terms, which have damping factors as I mentioned before. I had to do the calculation to actually see the step discontinuity. Has this discontinuity come from a sloppy parametrisation of empty space, or does it correspond to a weird distribution of matter at z=0? That's another question. I mention all this because, eg, a cone is flat space everywhere, except at a point where it has infinite curvature. That's why you must be careful and look at the topology, global properties, and so on. It seemed to me you were just blissfully saying it was flat space because a purely formal re-scaling does it. Does Genady's example answer Marcus' question then?
  8. When you construct the Riemann tensor, second derivatives of the metric coefficients are involved, as you well know. As you didn't address my question (only half of it), I'll repeat: Those are certainly involved in the calculation of the Riemann tensor, aren't they?
  9. No, it's ok. It was just me splitting hairs, as usual.
  10. Are you sure? What is H'(z) and H''(z)? You might be right, and I wrong. You might be wrong, and I right. Or we both right or wrong, and not know. In any case, it's interesting.
  11. Tunneling is about one particle going through a barrier a few angstroms thick --I'm thinking Josephson junctions and the like. Star Trek stuff is about sending 1025 atoms many miles away, and these atoms remembering who you where and what exactly you were thinking on the other side. Quite a feat in comparison. For the dark side of teleportation you might want to consider The Fly. Either the 1986 film, or perhaps the classic, 1958.
  12. Sorry, Genady. That's what I should have said. Should have meant? In the general theory of PDE's, as you probably know, the eqs. can be proven to have unique solutions for any complete set of initial/boundary data iff the highest order derivatives can be solved in terms of the rest by Lipschitz-continuous functions (simply continuous is a stronger condition that of course suffices). g''=F(g',g,T,x) where (schematically) g is the "function to be solved for", F is a function, T is a source, and x is the point. Heaviside's step function is not continuous, but you're right that the "damping factors" z² and z⁴ seem to patch up the zeroth and first derivatives, but not the second. I'm next to sure that the moment you second-differentiate, you'd run into problems though. I wasn't critizising your example. I understood the motivation, and it's very nicely devised.
  13. Ah, yes! But this introduces discontinuity in the metric by hand. So it's not a surprise that PDE's (never mind their being non-linear or having a good deal of geometric meaning) cannot encompass them.
  14. I suppose that's what @MigL meant when he said 'sort of'. Here: Just for the record, I don't see the connection either. Not to mention nobody mentioned space-time curvature here. And nobody should.
  15. Just to clarify, I meant reality according to Einstein: (from the famous EPR paper) Quantum mechanics does not necessarily deny reality (in this sense) for a wide range of system properties (energy, momentum, spin, orbital angular momentum...) Position is not one of them because position is not a conserved quantity. What it does is deny reality for certain property-pairings that are classified as incompatible, at the same time. See how naturally the question of causality pops up when one examines this question of reality?: At the same time. There's the relativistic rub. What if a system has spatial extension and one measures one property here and another (incompatible) property there? In QM there is a tension between reality and causality, you see. This 'tension' is more clearly perhaps expressed by way of Bell's theorem. And, as MigL says, every time you measure, this reality is 'updated'. I prefer this term to 'established'. But I have no objection to 'established'.
  16. The mathematics and the rules to apply them are very precise. How to swallow the metaphysical pill is another matter. I was in the process of answering you when exchemist's answer blinked on my screen. I don't think it's about a subtle way of motion, or measuring "things" from a recent past, or something of the kind. I think it's about this beneath-reality physical variable that we call the probability amplitude. I carries energy and momentum and is coupled to currents. It's as physical as it can be. But it only gives you potentialities, what can happen, not what does happen.
  17. Good one. Here's the catch: (my emphasis on OP's source) Nearly a 100 years in the books. And still people, when in doubt between reality and causality, would rather sacrifice the latter. It is reality that is dead as a sharp concept, even though it is a very good approximate one. This goes to show how adhesive the concept of classical reality is: "It's either this or not this" is harder to give up than smoking.
  18. That's an outstandingly good question IMO. I know inverse problems in physics are notoriously difficult. Eg, the inverse-scattering problem: Given the scattering properties, find the scatterer. What you're proposing, in terms of scattering problems, would be: Given any scattering, can I always find a scatterer that does it? My guess would be no too. That you can always find a T that does it, even though you might have to make it un-physical. But I cannot go beyond the guess at this point.
  19. Yes. Scale can dilute our delusions. It shouldn't should it? Einstein seems to have been of the same opinion. I find it very difficult to disagree with that. The most likely candidate to smooth things out is, of course, quantum mechanics. And Genady is very hard to win over, probably because he lives on an island.
  20. The argument that always creeps in is that, looks (and is) smooth enough, while, doesn't so much, although it's equally smooth. It's just that the curvature at the corners is enormous as compared to scale 1. These are called squircles, btw, and they're fascinating.
  21. I always use pressing Ctrl+hyperlink, as suggested by Swansont. Fast.
  22. Amen OP confused "theory of everything" with "everything I think is a theory".
  23. OK. Then the Wikipedia article needs editing, because it's very confusing. It explains nothing of that. Not a thing.
  24. Sorry I missed this. There seems to be a correspondence between one and the other, right?
  25. Here's what I mean: According to Wikipedia, the definition of LCT's is, \[ X_{(a,b,c,d)}(u)=\begin{cases} \sqrt{\frac{1}{ib}}\cdot e^{i\pi\frac{d}{b}u^{2}}\int_{-\infty}^{\infty}e^{-i2\pi\frac{1}{b}ut}e^{i\pi\frac{a}{b}t^{2}}x(t)\,dt, & \text{when }b\ne0,\\ \sqrt{d}\cdot e^{i\pi cdu^{2}}x(d\cdot u), & \text{when }b=0. \end{cases} \] So it's just an integral transform acting on the time-dependent part of the position-variable representation of the total wave function. IOW, this transformation does not depend on colour, electric charge, weak hypercharge, spin, or any of that. Nothing! It doesn't even touch those indices. How can it provide classification into irreducible representations according to colour, electric charge, weak hypercharge, spin and all of that? I don't see how it does, and I can't picture any way in which anybody can tell me how it does unless they have a theory, as promised in the wikipedia article: What theory? Where is the theory? Does anyone have a theory to explain this utterly unbelievable statement that a group acting on one space helps classify objects defined in another (completely unrelated) space!!!? I know about Cartan, and Gell-Mann matrices, and unitary representations of compact groups. I know all of that. But it doesn't even begin to address any of my concerns about this.
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