Everything posted by Genady
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Gravitational wave generation of integrating blackholes
If I understand your question correctly, then this diagram answers it. See the parts (d) and (e). The source of the waves is on the left, the faraway receptor is on the right: and the explanations: As you see, in the first approximation, i.e., in the dipole case (d), the contributions cancel exactly even for different masses, contrary to your assumption in the OP ("the difference in mass of the two"). The outgoing wave survives because of the quadrupole (e).
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"What it is like to see the color red"
Thank you. Well, I think that the OP has been answered (to my satisfaction.)
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"What it is like to see the color red"
As we all know, the image I've presented earlier (https://www.scienceforums.net/topic/132496-what-it-is-like-to-see-the-color-red/?do=findComment&comment=1250647) belongs to phenomena called "optical illusions". But is it an illusion? By the definition in Optical illusion Definition & Meaning - Merriam-Webster, optical illusion is But is it misleading? What is there misleading about it? It could be considered misleading if we expected the brain to perceive identically lights of equal frequencies. But why would we expect it? Why would brain evolve in this way? What it'd be good for? Brain is not a laboratory instrument. It is an organ that helps us to survive. Colors in the brain is a phenomenon by itself, which is related to but different from the colors in light. For example, I can imagine an advantage of seeing differently a red fruit hanging high on a tree against light sky background (not interesting) and the same red fruit hanging low against green foliage background (useful).
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"What it is like to see the color red"
I don't think there are aliasing bars (if I understand correctly what you refer to) in the original. They are added by the zooming algorithm when the image is enlarged.
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"What it is like to see the color red"
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Schwarzild orbits?
No, not at all. It is just short. This diagram shows how short is proper time of a falling particle between the event horizon, r/M=2, and the singularity, r/M=0:
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Schwarzild orbits?
When their event horizons join they quickly make one black hole.
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Schwarzild orbits?
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What became of the Toad?
Do you know if this is also why my dogs chew gravel sometimes?
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Gravitational wave generation of integrating blackholes
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"What it is like to see the color red"
This is perhaps why red is my wife's "favorite color", while I don't even know how a color can be "favorite."
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"What it is like to see the color red"
I see arguments regarding interpretations of that mental experiment. Somehow, I don't see what the question is.
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EPR, Bell and (none-)locality again
The normal spacetime.
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"What it is like to see the color red"
My null hypothesis is that if we can examine how our neurons react to the same color, we find that their reactions are generally somewhat similar but not the same in details in different heads. Moreover, they are not the same in the same head at different times and conditions.
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"What it is like to see the color red"
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EPR, Bell and (none-)locality again
The Cellular Automaton Interpretation of Quantum Mechanics | Physics Today | AIP Publishing
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"What it is like to see the color red"
This sentence (see the title) has appeared several times recently in this forum. Could somebody please explain to me what it means? I honestly don't understand.
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EPR, Bell and (none-)locality again
How do you know this?
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The Empty Brain
i.e., as long as brain is a 'black box,' I agree. I know that now, it pretty much is. I think, I know now what the quoted sentence referred to. Thanks a lot.
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The Empty Brain
Certainly, any static picture, even one that includes not only the connectome map but also momentary distribution of all neurotransmitters etc., is not sufficient. Dynamic data are necessary. Here is another analogy, weather. Static satellite pictures of current weather conditions do not allow to make predictions. Dynamic data are necessary. But I doubt that it necessitates knowledge of the entire history of Earth. Cf.,
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The Empty Brain
I guess the snapshot of a state is not the same as the state. Using a mechanical analogy again, is a snapshot like a 'position' of particle, while a state is its 'position and momentum'?
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Find the angle
This is correct. +1
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Find the angle
- The Empty Brain
I think my lack of understanding of this point is caused by my lack of understanding of what "to reconstruct what things mean" means. My point (perhaps different from the one in question) is that to describe the next state of a system all one needs to consider is its current state and the current state of all external factors that affect it.- Find the angle
My source tells me that people come up with quite a wide range of answers: Unfortunately, it does not explain what kind of errors they make. - The Empty Brain
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