Jump to content

ahmet

Senior Members
  • Posts

    435
  • Joined

  • Last visited

  • Days Won

    1

Everything posted by ahmet

  1. mmm,maybe I might change my idea. because I remember at one of my BSc class that one of my hodja was using something like this: "continuous Almos at everywhere" but again I am sure on one thing. to make it in the conformity of mathematical sense, you need to formulate it. and I do not remember the formula of that things he said (given above) mm yes presumably I am correct in this expression. because when I asked to google what "continuous almost everywhere " means ,it returned me this quotation given below this explanation includes one important keyword "measure" thus it is presumably relevant to real analsysi ("measure theory")
  2. I am not sure what you meant here. but this might prove that it was physical (or in other words,it might convince you). (I could not be sure whether it complies this forum's rules ,therefore I am uploading the picture instead)
  3. hi, [math] \frac x^{2}{1^2} - \frac y^{2}{\frac {1}{ \sqrt {92}^2} [/math] and this is just hyperbola's equation. therefore, it is one of quite simple curves
  4. I do not imply the mirror ,but .. the appearances you will obtain ,will have at inifitive count.
  5. well, assume please you use two flat mirror one is just at the opposing side another.
  6. I think it is physical,too. because I think I can examplify it..
  7. to me,,"almost infinite" definitely does not make sense at this stage. but if we were implying some contexts,for instance, in real analysis (some relevant subtitles would be : lebesgue integral, limits specifically in this context, lebsgue space,etc.)then I m not sure.
  8. concerts seems logical but not so much 🌙, and I do not think that todays musicians are able to ern money via selling cd/mp3 ..I also think that my 7 years old cousin almost will not learn what the cd is. It is odd ☢️ thanks for the information. and are there any statistics taken from youku?
  9. are there numeric expressions to clarify the case? For instance if we assume that between 5000000-500000000 yearly watch target how much money will this bring as income?
  10. I think you can find some contexts in Schaum's Outlines / Linear Algebra. (book series) if you would like to further improve yourself,then I can recommend Algebra for you under the same source series.
  11. hello, I believe I am a good composer and music producer , but unfortunately currently this consists of only a belief. but as you know,all we are trying to implement our plannings and or the things that we imagine. Therefore,I am planning to fly to romania. as far as I know ,they are good in popular musics. have you any recommendation for me? I shall try to remain open to ideas...
  12. I understand. physics and mathematics are different disciplines. as a matheatician,to me,if you would like to do mathematics ,then you need to concentrate on definitions and theorems.
  13. if you meant the derivation function,then your implication is incorrect! because [math] f(2x)=f((x^{2}+c)') [/math] but [math] 2x \ne x^{2}+c [/math] if you meant whether 1-1 is equivalent of this proposition (given below) ,then yes! "f(x)=f(y) --->> x=y" but if you are asking whether ,being well defined is equivalent meaning of 1-1 ,then no. let see one example given in the figure.
  14. you can use other constants that I did not write. (e.g.: one of other curvature might be written as: x^3 + b ...) but this should be written like something this: [math] \frac {x^{2}}{a^{2}}+\frac {y^{2}}{b^{2}}+ \frac {z^{2}}{c^{2}}=1[/math] this is elipsoid, but I can't find the correct equation for that curvial object above. oh,my hodja from my BSc has replied just now. this thread can be closed ... thanks to my lovely hodja.
  15. could someone help me please,I need this object's mathematical expression in cartesian coordinates.(The drawn area 3d coordinates please) Thanks in advance.
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.