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bahozkaleez

limits of different functions

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bahozkaleez    0

I am currently reading a book on calculus and I have come across a problem which I can't solve. I do feel like the answer is something simple. Please note that I am fairly new to calculus.

 

post-123106-0-88619400-1483295327.png

 

Thank you.

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studiot    1161
Posted (edited)

What is your definition of f'(x) ?

 

Are you sure the question does not say

 

If f(x) is differentiable at xo then prove that.....etc ?

 

Consider the differentiability of f(x) = |x| and of f(x) =x2 at xo = 0

 

 

 

Edited by studiot

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Function    76

What is your definition of f'(x) ?

 

Are you sure the question does not say

 

If f(x) is differentiable at xo then prove that.....etc ?

 

Consider f(x) = |x| at xo = 0

 

I've lost all my maths skills (except for statistics), but we always denoted the derivative function of f(x) as f'(x).

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studiot    1161

 

I've lost all my maths skills (except for statistics), but we always denoted the derivative function of f(x) as f'(x).

 

Yes, that's right the derived function is f'(x).

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mathematic    65

Place [latex] -f(x_0)+f(x_0)[/latex] in the middle of the numerator. It is obvious what follows.

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Sriman Dutta    44

By defining f(x)=x^2+3x or anything else, you can put its value in the equation and get the desired results.

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zztop    11
Posted (edited)

I am currently reading a book on calculus and I have come across a problem which I can't solve. I do feel like the answer is something simple. Please note that I am fairly new to calculus.

 

attachicon.gifmathz.PNG

 

Thank you.

[latex]\frac{f(x_0+\Delta x)-f(x_0-\Delta x)}{2 \Delta x}=\frac{f(x_0+\Delta x)-f(x_0)+f(x_0)-f(x_0-\Delta x)}{2 \Delta x}[/latex]

 

"mathematic" beat me to it

Edited by zztop
  • Upvote 1

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bahozkaleez    0
Posted (edited)

[latex]\frac{f(x_0+\Delta x)-f(x_0-\Delta x)}{2 \Delta x}=\frac{f(x_0+\Delta x)-f(x_0)+f(x_0)-f(x_0-\Delta x)}{2 \Delta x}[/latex]

 

"mathematic" beat me to it

Thank you, this really helped me.

Edited by bahozkaleez

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