problem solved

Edited January 29, 201510 yr by anonymousking123

How often do you have to perform this operation to get a specific x?

 

once

once

the first person to post such formula in private. The formula must work in all cases, and be comutationally feasible

<script>
var equation= "(x²-1)² / (4*x*(x²+a*x+1))";
var a=0;
var b=10;
while(a<b)
{
var equation = equation.replace("x", "(x²-1)² / (4*x*(x²+a*x+1))");
a=a+1;
}
document.write(equation);
</script>

Where b is the specific new_x you are looking for so for new_x=10

 

(((((((((((x²-1)² / (4*x*(x²+a*x+1))²-1)² / (4*x*(x²+a*x+1))²-1)² / (4*x*(x²+a*x+1))²-1)² / (4*x*(x²+a*x+1))²-1)² / (4*x*(x²+a*x+1))²-1)² / (4*x*(x²+a*x+1))²-1)² / (4*x*(x²+a*x+1))²-1)² / (4*x*(x²+a*x+1))²-1)² / (4*x*(x²+a*x+1))²-1)² / (4*x*(x²+a*x+1))²-1)² / (4*x*(x²+a*x+1))

 

where x=9 if I was being less lazy I could calculate it as well

Edited January 29, 201510 yr by fiveworlds

so that would be the correct response then?

You can run it yourself in a .html file just copy and paste it into notepad. Of course over 100000 is kinda slow on my computer so there are some limitations to it. If I was to have it calculated I would run the above script as php and then use that to generate the javascript code to give me an answer.

The original problem has been deleted so I can't comment on that. But ...

 

I would run the above script as php and then use that to generate the javascript code to give me an answer.

 

Why use PHP to generate Javascript? The PHP can generate whatever output the Javascript was going to.

 

Unless the deleted problem asked for a Javascript solution?

problem solved

 

!

Moderator Note

Please, don't EVER delete the opening post! You aren't the only person here to learn.