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Deuterium: Where does it come from, where does it go?


vampares

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Deuterium is a stable isotope of hydrogen.

 

If hydrogen (protium, thats hydrogen-1) is bombarded with neutrons, why does this not create deuterium?

 

If I am correct fission occurs (do correct me) because particles conjoin with isotopes that were previously stable. Now the isotope has an extremely short half-life and decays.

 

Well what if the particles are not intrinsically repelled by classical physics and the particles collide?

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Deuterium is a stable isotope of hydrogen.

 

If hydrogen (protium, thats hydrogen-1) is bombarded with neutrons, why does this not create deuterium?

 

 

I have a vague recollection that H-2 doesn't have a real excited state — the proton and neutron will split at a lower energy. That makes it difficult to form, since the binding energy must be emitted immediately. So it has a very small cross section for formation.

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Protium does form deuterium when absorbing a neutron. It's the reason to prefer heavy water when neutrons are scarce. For instance a reactor can work with natural uranium, but only using heavy water as deuterium absorbs neutrons very little and oxygen almost doesn't it anyway.

 

You have the neutron cross-sections there, many thanks to Nist:

http://www.nndc.bnl.gov/sigma/index.jsp?as=1&lib=endfb7.1⊄=10

a click on "(n, gamma) plot" gives you the absorption versus neutron energy

http://www.nndc.bnl.gov/sigma/getPlot.jsp?evalid=14960&mf=3&mt=102⊄=10 like 0.3 barn at 25meV=300K

then you may choose rather Z=2 for deuterium and see 0.4 millibarn at 25meV

(or take 600K=50meV in a reactor)

 

That same reasons tells you that deuterium isn't very good to produce tritium. Lithium is easier - but deuterium is already there in a Candu reactor.

 

They have the (n, inelastic) graphs for O-16 and O-17, showing negligible cross-sections at 25meV.

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