Hey guys. I'm interested in knowing how you get to:

 

[math]t = \gamma t'[/math]

 

...from:

 

[math]t' = \gamma (t - \frac{vx}{c^2})[/math]

I could solve it for you (probably), however, i want to know, for my own derivation, what the units you are using.

 

By the way, it seems almost as though someone has replaced mass with time, am i wrong...?

I could solve it for you (probably), however, i want to know, for my own derivation, what the units you are using.

Hi Tom - Just a reminder... Please, please, please don't do the work for the requestor. Ideally, you would explain to them how to work through it, maybe splitting the basics into steps without giving away the answer. More than a policy here at SFN, it's actually a good practice in life.

Hey guys. I'm interested in knowing how you get to:

 

[math]t = \gamma t'[/math]

 

...from:

 

[math]t' = \gamma (t - \frac{vx}{c^2})[/math]

 

To begin with, appart from the transformation you have given here (Lorentz transfirmaton for time) one also needs the transformation for [math]x[/math]. I.e.:

 

[math]x'=\frac{x - \upsilon c}{\sqrt{1-\frac{\upsilon^2}{c^2}}}[/math]

 

Having them both, you can solve a system of 2 equations for 2 unknowns: [math]x[/math] and [math]t[/math]

Hi Tom - Just a reminder... Please, please, please don't do the work for the requestor. Ideally, you would explain to them how to work through it, maybe splitting the basics into steps without giving away the answer. More than a policy here at SFN, it's actually a good practice in life.

 

Oh my bad.

By the way, it seems almost as though someone has replaced mass with time, am i wrong...?

 

Yes. These are time dilation equations. Mass does not appear in them.

I don't recognise the v(x) part, this is why i may have asked this question.