l is perimeter

p is Pi

a is side

l_min=1=2pr

r=1/(2p)

standard area = pr^2 = 1/(4p)

For square a^2=1/(4p)

a=1/(2×p^1/2) then

l=2/p^1/2

For equilateral triangle:

l = (3^3/4)/(p^1/2)

For isosceles right triangle:

l = ((2^1/2)+1)/p^1/2

😛

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Edited September 14Sep 14 by Sensei

Is there a point of discussion here?

Let's define relative perimeter for any right triangle

Let's define equation for definition of relative perimeter of rectangle with sides a and b .

That doesn’t answer my question.