Jump to content


Senior Members
  • Content Count

  • Joined

  • Last visited

Community Reputation


About DimaMazin

  • Rank
  • Birthday 01/16/1970

Profile Information

  • Location
  • Favorite Area of Science

Recent Profile Visitors

10744 profile views
  1. What is wrong again?
  2. All my ideas are wrong. I think reality is simpler. Orbits of electrons and of particles in atom are increased due to increased space in gravitation. Therefore particles should more travel for a creation and a change of events . Later changes cause later photon radiation in atomic clock of gravitational observer.
  3. Next idea: Motionless mass has an energy for creation of own time, part of which is kinetic energy in another reference frame. Also mass has an energy for support of gravitation. When mass is falling in gravitation it firstly loses part of energy for creation own time and gets acceleration. When the mass is stopped in gravitation it has less energy for creation of own time and more energy for support of gravitation.
  4. Change of position of relativistic energy with mass and without mass creates change of time. My formula shows it.
  5. All humanity is stopped.
  6. Well. I am very wrong earlier. Let's consider next idea. Er=gamma*mc2 Er=mc3/(c2-v2)1/2 (mc3/Er)2=c2-v2 v2=c2-m2c6/Er2 v=c(Er2 - m2c4)1/2/Er dt=dx/v dt=Erdx/(c(Er2 - m2c4)1/2 I have made formula of dt definition.
  7. Today we can lose momentum because p = Er*v/c2
  8. Er is relativistic energy https://en.wikipedia.org/wiki/Energy–momentum_relation Er2 = m2c4+p2c2 Er2= m2c4 +m2v2c4/(c2-v2) Er2=m2c4+m2dx2c4/(c2t2-dx2) Er2c2t2 - Er2dx2=m2c6t2 - m2c4dx2+m2c4dx2 t2=Er2dx2/(Er2c2 - m2c6) t=Erdx/(c(Er2 -m2c4)1/2 t=Erdx/(c(p2c2+m2c4 - m2c4)1/2 t=Erdx/(pc2)
  9. At all t = Er* dx/(|p| c2) Moved relativistic energy exists in motionless object
  10. t has second m has kilogram q has second * kilogram If quantity of counteraction of forses to motion doesn't exist then how Swansont defined different quantities of it for different masses?
  11. t = q/m t is time of observer q is quantity of counteraction of forces to motion of motionlees object m is mass of motionless object
  12. t'c/(c2 - v2)1/2 = t t2=t'2c2/(c2-v2) t2=t'2c2/(c2-dx2/t2) t'2c2/(t2c2-dx2)=1 t'2c2=t2c2-dx2 t'2c2/c2+dx2/c2=t2 t2=dx2/c2+t'2 t=(dx2/c2+t'2)1/2 We can not use the equation for solve of my task because we should know more data I am wrong there.
  13. You can measure short distance by ruler, then you can define dx. Scientists can measure large dx of light by brightness of supernova. Then speed of travel=0
  14. We can use variables dx is distance between the planets t1 is time of start of travel t2 is time of end of travel t' is time of traveling clock at end of travel t2 - t1 =(( dx)2/c2 +t'2)1/2 We need to define t1 t1=t2 - ((dx)2/c2 + t'2)1/2 Forces exist in mass. Mass can not exist without forces.
  15. Let's solve such task: We know distance between the Earth and green planet. Green traveler turned on its clock at start of travel to us. The traveler was traveling at different and unknown speeds. Time of start of the travel is unknown and we should define it. The green traveler has errieved to us and showed time of traveling clock. I can simply solve the task using my equation. Can you solve the task simpler?
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.