Jump to content

Featured Replies

The Three Body Problem in physics concerns the issue that it becomes incredibly complex to calculate the orbits of three bodies, when two are easy. Recently, it has proven to have inexplicable "Islands of Stability" and it occurred to me its a way to prove fuzzy logic is based on Paradoxical Monty Carlo statistics, and can be used to simplify all of quantum mechanics.

On "Let's Make A Deal" Monty Hall offers you a final chance to swap between two doors. Classic statistics say it's just a 50/50 chance, but fuzzy logic says it's better to swap, giving Monty Hall the "Home Team Advantage", where it's actually more productive just to play the game for fun, then to over-think the problem. Note, this also explains the Quantum Observer Effect and all of physics as expressing a Singularity.

I have the math for it if anyone wants it, but it's linguistic-mathematics that are like nothing you've ever seen.

Edited by Wu Li Heron

55 minutes ago, Wu Li Heron said:

On "Let's Make A Deal" Monty Hall offers you a final chance to swap between two doors. Classic statistics say it's just a 50/50 chance, but fuzzy logic says it's better to swap

Nothing to do with fuzzy logic, it’s about properly applying logic. There’s added information (the revealed door is not chosen randomly)

If you want to discuss something, post it. “Teasing” rapidly becomes tiresome.

  • Author
25 minutes ago, swansont said:

Nothing to do with fuzzy logic, it’s about properly applying logic. There’s added information (the revealed door is not chosen randomly)

If you want to discuss something, post it. “Teasing” rapidly becomes tiresome.

You are ignoring the fact it is a "No Brainer", that gives an advantage to just playing the game for fun.

18 minutes ago, Wu Li Heron said:

You are ignoring the fact it is a "No Brainer", that gives an advantage to just playing the game for fun.

What do you mean by this?

When the contestant first chooses the door, there is a 1 in 3 chance that this door contains the prize, and a 2 in 3 chance that it doesn't contain the prize. When the host subsequently reveals what is behind one of the other doors, this does not in any way alter the probabilities of the contestant's original choice.

11 hours ago, Wu Li Heron said:

I have the math for it if anyone wants it, but it's linguistic-mathematics that are like nothing you've ever seen.

Then post it if you want to discuss it.

Otherwise there is nothing to discuss and this thread is done.

11 hours ago, Wu Li Heron said:

mathematics that are like nothing you've ever seen.

I think the people who have been here a long time, have seen more types of math from a spectrum of people like you and I than we could imagine. Don't know this game, sounds like ‘deal or no deal’ in the uk.

I would like to see the math though out of curiosity as not been here long. And how does picking an abstract door being a 1 or 0 from 3 doors with only 1 door being able to contain a 1 anything close to calculating orbit of 3 bodies? As for fuzzy logic… whats that?

Edited by BuddhasDragon23

27 minutes ago, BuddhasDragon23 said:

Don't know this game, sounds like ‘deal or no deal’ in the uk.

It's funny that you mention Deal or No Deal because I have often wondered if this has a Monty Hall problem aspect to it. I don't think it does actually. The Monty Hall problem is quite well known for its counterintuitive result. Even MythBusters had an episode that dealt with this problem.

Edited by KJW

Thx for the link. I get it now, and i kinda worked out the probabilities of winning are improved by switching are improved by the initial choice effecting the outcome of the rule forced on the host and the door they open.

in deal or no deal there is no rule on the host to reveal a box based on any choice of the contestant, so the conditions of the swap shouldn’t be effected except by how the game plays out. I think having the swap makes a difference as it is like having the choice to pick two boxes to keep till the end, not just the one box they originally pick.

I think it might have an available effect as boxes are revealed, you could change the box you want to keep till the end, so if you say at start box 1 has top prize and 2 next keeping them to the end is best but if either of those amounts are revealed you know they are not, but then out of all remaining you still wont know where the 3rd, 4th, 5th best prizes are. Hmmm i think even having 2 out 20 if both unknown is no different as still comes down to 1 out of those two so still 1 out of 20.

1 hour ago, KJW said:

It's funny that you mention Deal or No Deal because I have often wondered if this has a Monty Hall problem aspect to it. I don't think it does actually. The Monty Hall problem is quite well known for its counterintuitive result. Even MythBusters had an episode that dealt with this problem.

My boss and I were discussing this, back in the day, and he suggested it’s easier to imagine it if you imagine it’s 100 doors. You pick one, and then 98 doors are opened up. Was your 1% chance correct, or is it that one door that’s still closed.

16 minutes ago, swansont said:

My boss and I were discussing this, back in the day, and he said it’s easier to imagine it if you imagine it’s 100 doors. You pick one, and then 98 doors are opened up. Was your 1% chance correct, or is it that one door that’s still closed.

It would've been interesting if MythBusters had carried out this modified version of the problem to see if people who think the outcomes are equally likely in the original 3-door problem still think the outcomes are equally likely in the 100-door version of the problem. I suspect that such people would still stay with their original choice because I don't think the obviousness of the 100-door problem would be apparent to those who do not understand the solution of the 3-door problem. On the other hand, if the host opened 98 doors, with your chosen door and say the 57th door left unopened, that might create a bit of suspicion, perhaps leading to the correct answer.

Edited by KJW

Here is another version of the Monty Hall question.

A mathematician has two children.

You ask if at least one of them is a boy.

She answers yes, at least one of my children is a boy.

So what are the chances that she is a mother of two boys ?

This version demonstrates very clearly that it depends upon what question you ask to what the chances are.

@KJW if you answer this please put the answer in a spoiler.

  • Author

How many crackpots there are in the world is not relevant to the question, please stay on topic.

Answer the question: Why would a bot have an advantage on Let's Make A Deal, merely because it doesn't over-think the problem. The bot doesn't know fuzzy logic, it just swaps the doors.

The Wisdom of Collective Ignorance | Hip Forums

Edited by Wu Li Heron

9 minutes ago, Wu Li Heron said:

How many crackpots there are in the world is not relevant to the question, please stay on topic.

Answer the question: Why would a bot have an advantage on Let's Make A Deal, merely because it doesn't over-think the problem. The bot doesn't know fuzzy logic, it just swaps the doors.

The Wisdom of Collective Ignorance | Hip Forums

A mathematical fact.

You have exactly 5 posts available in your first 24 hours so it is unwise to waste them.

You could add to post number 3 something useful and on topic by way of the edit post function, available by clicking on the 3 dots in the top right hand corner of your post.

More than one member has now said post the maths you offered.

  • Author

I have provided a link to my math. It is over 200 pages of linguistic-math that is word perfect and complete, Nobel caliber, and enough to make the Nobel committee throw up.

So you didn't read the rules that here you signed up to before you posted .

I should not have to go off site to read the substance of your query or hypothesis.

  • Author

I gave you the substance, A bot paradoxically has an advantage to over-thinking the problem. If math is not based on reality, I'd look for another website to hang out at.

Edited by Wu Li Heron

3 hours ago, Wu Li Heron said:

I have provided a link to my math. It is over 200 pages of linguistic-math that is word perfect and complete, Nobel caliber, and enough to make the Nobel committee throw up.

Moderator Note

Rules require material for discussion be posted here, not via links or uploads.

And: yeah, right.

(In any event, there isn’t a Nobel for math)

On 9/22/2025 at 11:22 PM, Wu Li Heron said:

On "Let's Make A Deal" Monty Hall offers you a final chance to swap between two doors. Classic statistics say it's just a 50/50 chance, but fuzzy logic says it's better to swap,

Just write them out and it becomes obvious.

IMG_20250925_093320_462.jpg

On 9/23/2025 at 12:49 AM, Wu Li Heron said:

You are ignoring the fact it is a "No Brainer", that gives an advantage to just playing the game for fun.

Is it fun if all you do is swap every time…. Boring. If it is financially rewarding, you must be loaded .. nice

Seems obvious to me. The one initially chosen has a 33 1/3 % chance of being the correct choice. The one left has a 50% chance of being correct.

(using 3 choices of course)

Edited by npts2020
clarification

2 hours ago, npts2020 said:

Seems obvious to me. The one initially chosen has a 33 1/3 % chance of being the correct choice. The one left has a 50% chance of being correct.

(using 3 choices of course)

Not if you write out the outcomes. You go from 33% to 66% if you swap. I wrote it out above.

20 hours ago, BuddhasDragon23 said:

Is it fun if all you do is swap every time…. Boring. If it is financially rewarding, you must be loaded .. nice

That is not the point of the game, it is to illustrate a counterintuitive probability outcome.

5 hours ago, pinball1970 said:

Not if you write out the outcomes. You go from 33% to 66% if you swap. I wrote it out above.

That is not the point of the game, it is to illustrate a counterintuitive probability outcome.

Fairdincoomz

9 hours ago, npts2020 said:

Seems obvious to me. The one initially chosen has a 33 1/3 % chance of being the correct choice. The one left has a 50% chance of being correct.

(using 3 choices of course)

6 hours ago, pinball1970 said:

Not if you write out the outcomes. You go from 33% to 66% if you swap. I wrote it out above.

That is not the point of the game, it is to illustrate a counterintuitive probability outcome.

I did note in my post about Monty Hall that the exact wording of the question makes a significant difference to the answer.

My example makes this easier to see because we are not present to witness what the game show host says.

3 hours ago, studiot said:

I did note in my post about Monty Hall that the exact wording of the question makes a significant difference to the answer.

I only know the one version.

Three doors behind one a car, the other two have goats.

You pick door 1 (say) and the host then opens a door (2 say) revealing a goat and gives you the option to stick or swap.

What do you do?

On 9/23/2025 at 10:25 PM, studiot said:

Here is another version of the Monty Hall question.

A mathematician has two children.

You ask if at least one of them is a boy.

She answers yes, at least one of my children is a boy.

So what are the chances that she is a mother of two boys ?

This version demonstrates very clearly that it depends upon what question you ask to what the chances are.

@KJW if you answer this please put the answer in a spoiler.

Spoiler Alert!

1/3

For two children, the possibilities are, along with their probabilities:

GG = 1/4

GB + BG = 1/2

BB = 1/4

But with GG excluded, the possibilities now are, along with their probabilities:

GG = 0

GB + BG = 2/3

BB = 1/3

Edited by KJW

Please sign in to comment

You will be able to leave a comment after signing in

Sign In Now

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.

Configure browser push notifications

Chrome (Android)
  1. Tap the lock icon next to the address bar.
  2. Tap Permissions → Notifications.
  3. Adjust your preference.
Chrome (Desktop)
  1. Click the padlock icon in the address bar.
  2. Select Site settings.
  3. Find Notifications and adjust your preference.