Jump to content

Given the reactions, how many Volts is the yield ?


Recommended Posts

Hello. 

Can someone teach me how a chemical reaction translates into potential differential Volts as a battery ?  These chemical reactions / equations for these elements / compounds :

image.thumb.png.618a71b95906b53ddf2579174291eb3f.png

 

Or as for a perhaps simpler case, the well known carbon-zinc vulgar cell yielding 1.5 volts.

Link to comment
Share on other sites

5 hours ago, Externet said:

Hello. 

Can someone teach me how a chemical reaction translates into potential differential Volts as a battery ?  These chemical reactions / equations for these elements / compounds :

image.thumb.png.618a71b95906b53ddf2579174291eb3f.png

 

Or as for a perhaps simpler case, the well known carbon-zinc vulgar cell yielding 1.5 volts.

Nernst law

Potontials with positiv voltage minus Potential with more negative voltage gives potential between the two electrodes

 

Here 1 V -(-0.26 V) = 1.26 V

 

 

Zinc -0,763 V  carbon-manganeseoxide +0,975 V

 

0,975V - (-0,763) = 1,738 V

 

Link to comment
Share on other sites

Posted (edited)

Thank you !  Nernst law... will dig into it.

And the figures you show come from an electronegativity table, or from a galvanic series table, the standard electrode potential table, the periodic table, or from other source am not aware of ?

If it is a compound and not an element; how is the potential determined ?  Should I had expected that 1.5V is actually 1.738 V or reverse  instead ?

Edited by Externet
Link to comment
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.