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Given the reactions, how many Volts is the yield ?

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Hello. 

Can someone teach me how a chemical reaction translates into potential differential Volts as a battery ?  These chemical reactions / equations for these elements / compounds :

image.thumb.png.618a71b95906b53ddf2579174291eb3f.png

 

Or as for a perhaps simpler case, the well known carbon-zinc vulgar cell yielding 1.5 volts.

5 hours ago, Externet said:

Hello. 

Can someone teach me how a chemical reaction translates into potential differential Volts as a battery ?  These chemical reactions / equations for these elements / compounds :

image.thumb.png.618a71b95906b53ddf2579174291eb3f.png

 

Or as for a perhaps simpler case, the well known carbon-zinc vulgar cell yielding 1.5 volts.

Nernst law

Potontials with positiv voltage minus Potential with more negative voltage gives potential between the two electrodes

 

Here 1 V -(-0.26 V) = 1.26 V

 

 

Zinc -0,763 V  carbon-manganeseoxide +0,975 V

 

0,975V - (-0,763) = 1,738 V

 

  • Author

Thank you !  Nernst law... will dig into it.

And the figures you show come from an electronegativity table, or from a galvanic series table, the standard electrode potential table, the periodic table, or from other source am not aware of ?

If it is a compound and not an element; how is the potential determined ?  Should I had expected that 1.5V is actually 1.738 V or reverse  instead ?

Edited by Externet

1 hour ago, Externet said:

If it is a compound and not an element; how is the potential determined ? 

Experimentally.

 

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