Genady Posted February 26 Share Posted February 26 (edited) \[\phi(x) \rightarrow \phi(x+\xi)=\phi(x)+\xi^{\nu} \partial_{\nu} \phi(x) + ...\] \[\frac {\delta \phi} {\delta \xi^{nu}} = \partial_{\nu} \phi\] \[\frac {\delta \mathcal L} {\delta \xi^{nu}} = \partial_{\nu} \mathcal L\] \[\frac {\delta \mathcal L[\phi, \partial_{mu} \phi]} {\partial \xi^{\nu}}=\partial_{mu} (\frac {\partial \mathcal L}{\partial (\partial_{mu} \phi)} \frac {\delta \phi} {\delta \xi^{nu}})\] Edited February 26 by Genady Link to comment Share on other sites More sharing options...
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