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calcium carbonate and salt reaction


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2 hours ago, observer1 said:

so no reaction occurs?

All four ions will remain in solution independently. If you evaporate the water, you may get a mixture of NaCl, CaCl2, NaOAc and Ca(OAc)2, since all are stable salts. However, to find out how much of each you get, you would need to determine the free energy of crystallisation (or solution) for them all, as some combinations will produce lower energy states than others, depending on the lattice energy and the entropy change. You may even get mixed salts like CaClOAc, if there is a suitably low energy crystal structure for that combination.  

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5 hours ago, observer1 said:

so basically no double displacement will occur when in water

No, because all the combinations are soluble. Generally you get that type of reaction when one of the possible salts is a lot less soluble than the others, i.e. it has a lattice that is so stable that the ions to prefer to form crystals than stay dissolved. In such a case, that salt will precipitate out, leaving behind the ions it does not need. 

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  • 8 months later...

But its strange its either the non metal swaps or the metal swaps, and then it satisfy the end result,  but out of the two you dont know.


But I think maybe you can tell, if one is cemented, and then your putting solution on the cement, and then u can see if its the metal or the non metal swapping for what the cement ends up being.


So if I were epsom salt solidified, and in sodium carbonate solution,   then if the nonmetal swapped id get magnesium carbonate cement.

If i were sodium carbon solidified, and epsom salt soltion, then id get magnesium carbonate cement if it were the metal swapping.


But maybe its a bit of both, I dont know,  but from what I experienced, it was the metal swapping, but I could be wrong.


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