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Everything posted by observer1

  1. pretty sure, reactivity series says it will occur. can't test it because I don't have a magnesium ribbon
  2. btw I forgot to mention that it only appears yellow when concentrated. When kept in a lot of water, the water appears transparent. Also, will I be able to break the proteins if I heat them, making it somewhat whiter?
  3. so like if the layer is not calcium acetate, I will remove it. I am doing this just to confirm because I can't find anything about this in google
  4. It was white eggs I basically was following this video, except i did not heat it to evaporate, I lift it to evaporate Link :-https://youtu.be/32vCLXTjnyQ
  5. yes, so is this yellow because of me using eggs or is something ELSE happening?
  6. when i filtered it, i say no insoluble particles
  7. So I basically wanted to make calcium acetate. So I took some vinegar and egg shells, mixed them and kept them in a container fr about about 3 weeks. I kept an excess of eggs and it finally stopped reacting. After that, I transferred the water and calcium acetate without the shells or the egg layer using a filter. I later left the cup to evaporate fr about 2 weeks and a mostly transparent, yellowish layer started forming on top. Is is calcium acetate?
  8. so in a reaction, if both the reactants and products are soluble in water, the reaction does not take place while if the product is not completely soluble in water, then the reaction is possible. Also if the reactants are no soluble in water, the reaction does not take place
  9. why does that happen? is it because here both sides completely dissolved while in the one I gave, Ca(OH)2 is slightly dissolved in water?
  10. so since Ca(OH)2 is slightly soluble and not completely, the reaction is not possible now i understand so, just asking, let's ASSUME Ca(OH)2 is also soluble, then the reaction will go back and forth?
  11. that was what I was just telling. Only the first reaction is possible because both the reactants completely are soluble in water
  12. That, frankly, is all I understood form the https://en.wikipedia.org/wiki/Solubility_chart link u sent. I was specifically looking about this reaction and that was the only difference I found(from the table u sent) if you can, can you pls explain this in a much simpler was or give a video for it?
  13. the first reaction is possible since both disassociate in water
  14. Ca(CH3COO)2 + 2NaOH ---> 2CH3COONa + Ca(OH)2 or 2CH3COONa + Ca(OH)2 ---> Ca(CH3COO)2 + 2NaOH
  15. so the problem is the hydrogen atom
  16. so in that reaction, the acetic acid will again react with CaCO3 to form calcium acetate again then why doesn't this reaction occur? Ca(CH3COO)2 + NaHCO3 ---> CaCO3 + CH3COONa + H2 here the hydrogen leaves as gas
  17. so is is VERY unlikely for the reaction to occur or it it basically not possilbe?
  18. The reaction between Ca(CH3COO)2 + Na2CO3 ---> CaCO3 + 2CH3COONa But why can't the same displacement reaction happen when NaHCO3 is added to Ca(CH3COO)2 Why does it show that no reaction happens when they are mixed? (type it in google)
  19. Here is what i did:- CaCO3(eggshells) + 2CH3COOH ---> Ca(CH3COO)2 + H2O + CO2 Ca(CH3COO)2 + 2NaHCO3 ---> 2CH3COONa + CaCO3(powder) + H2O + CO2 The problem is that there is nearly no way for you to know that if the residue on the bottom of the container is caco3 or nahco3 since both are white and insoluble. so i want a way to separate both of them
  20. the thing is it works in water but you need a lot of water to dissolve nahco3 and caco3 is also insoluble in water. using iso-propanol is also not working as both the caco3 and nahco3 get clumped together in the mixture. i cant find any solution online where one liquid is soluble to nahco3 but insoluble to caco3 would a context on why i am asking this give the answer?
  21. separation of two solids by mixing in a solution only one of it can dissolve in and getting deposition on the bottom for the other one.
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