~LL>~L

 

L=L

~L*L=0

0>~L

 

Then what if anything can ~L be equaled to?

Too little information given to draw a conclusion.

Is = operator of comparison?

Is > operator of greater than?

Is * operator of multiplication?

 

Do 0 means what it means for everybody in this world?

 

What does operator ~ ?

In programming it's bitwise NOT operator.

https://en.wikipedia.org/wiki/Bitwise_operations_in_C#Bitwise_NOT_.22.7E.22_.2F_one.27s_complement_.28unary.29

 

What is default operator between ~L and L in statement ~LL ?

Edited November 1, 20169 yr by Sensei

a. ~LL>~L

 

b. L=L

c. ~L*L=0

d. 0>~L

 

Then what if anything can ~L be equaled to?

 

1. For two object to multiply together to give zero © one of them MUST be zero - so either L or ~L is zero

2. From (a) and (1) we know that ~L is less than a product which must equal zero. Thus ~L is negative and has an absolute value which is not zero

3. From (d) we have confirmation that ~L is negative

4. From (b) we gain no new information

 

So presuming normal rules have applied we can say that L=0 and that ~L is negative

 

 

a. 0 times any negative is greater than any negative , 0>any negative

b. 0=0

c. any negative * 0 = zero

d. zero is greater than any negative

 

Thats all you can say L=0 , ~L<0

~LL>~L

 

L=L

~L*L=0

0>~L

 

Then what if anything can ~L be equaled to?

just a guess.

 

 

~L = anti-L, where L is some positive number?

 

 

Edited November 2, 20169 yr by TakenItSeriously

just a guess.

 

 

~L = anti-L, where L is some positive number?

 

 

 

What is anti-L ? The only possible meaning I can bring to mind is the reciprocal; but that would mean that L* ~L = 1.

Thank you everyone for trying this. I will release the answer in about a month from the original post.

What is anti-L ? The only possible meaning I can bring to mind is the reciprocal; but that would mean that L* ~L = 1.

 

lol, I don't know. It's pretty lame.

 

I started out thinking it was -1 since you could prove 1= -1 using imaginary numbers until I saw I had misread the problem somehow and tried to fix it. next thinking it could involve some kind of logical equation which took me on a weird tangent. It's dumb, I know.

Edited November 11, 20169 yr by TakenItSeriously

Disambiguate:

~(LL)>~L

OR

(~L)L>~L

~(L*L)=0

OR

(~L)*L=0

 

1. For two object to multiply together to give zero © one of them MUST be zero - so either L or ~L is zero

2. From (a) and (1) we know that ~L is less than a product which must equal zero. Thus ~L is negative and has an absolute value which is not zero

3. From (d) we have confirmation that ~L is negative

4. From (b) we gain no new information

 

So presuming normal rules have applied we can say that L=0 and that ~L is negative

 

 

a. 0 times any negative is greater than any negative , 0>any negative

b. 0=0

c. any negative * 0 = zero

d. zero is greater than any negative

 

Thats all you can say L=0 , ~L<0

Great job

imatfaal, I made this little problem up in 10 minutes time. I decided to release the answer early for the holidays.

~L<0, funny I put the answer in visible site and still people were having a tough go at it. ~L= any negative number!

Got any easier questions?

You didn't disambiguate.

 

So given ~(L*L)=0

 

As ~0 [math] \neq [/Math] 0

Therefore L [math] \neq [/Math] 0

Edited December 1, 20169 yr by AbstractDreamer