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DimaMazin

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Everything posted by DimaMazin

  1. Simultaneity is ratio of quantities of changes between determinations of distances and positions.
  2. We can not use that method when we don't know unknown phenomenon with time. Therefore firstly we should define what is unknown then maybe it is a time. I think we don't know quantity of exchange of energy through space . Then t = q / Er t is time q is quantity of exchange of energy through space Er is relativistic energy
  3. All my ideas are wrong. I think reality is simpler. Orbits of electrons and of particles in atom are increased due to increased space in gravitation. Therefore particles should more travel for a creation and a change of events . Later changes cause later photon radiation in atomic clock of gravitational observer.
  4. Next idea: Motionless mass has an energy for creation of own time, part of which is kinetic energy in another reference frame. Also mass has an energy for support of gravitation. When mass is falling in gravitation it firstly loses part of energy for creation own time and gets acceleration. When the mass is stopped in gravitation it has less energy for creation of own time and more energy for support of gravitation.
  5. Change of position of relativistic energy with mass and without mass creates change of time. My formula shows it.
  6. Well. I am very wrong earlier. Let's consider next idea. Er=gamma*mc2 Er=mc3/(c2-v2)1/2 (mc3/Er)2=c2-v2 v2=c2-m2c6/Er2 v=c(Er2 - m2c4)1/2/Er dt=dx/v dt=Erdx/(c(Er2 - m2c4)1/2 I have made formula of dt definition.
  7. Today we can lose momentum because p = Er*v/c2
  8. Er is relativistic energy https://en.wikipedia.org/wiki/Energy–momentum_relation Er2 = m2c4+p2c2 Er2= m2c4 +m2v2c4/(c2-v2) Er2=m2c4+m2dx2c4/(c2t2-dx2) Er2c2t2 - Er2dx2=m2c6t2 - m2c4dx2+m2c4dx2 t2=Er2dx2/(Er2c2 - m2c6) t=Erdx/(c(Er2 -m2c4)1/2 t=Erdx/(c(p2c2+m2c4 - m2c4)1/2 t=Erdx/(pc2)
  9. At all t = Er* dx/(|p| c2) Moved relativistic energy exists in motionless object
  10. t has second m has kilogram q has second * kilogram If quantity of counteraction of forses to motion doesn't exist then how Swansont defined different quantities of it for different masses?
  11. t = q/m t is time of observer q is quantity of counteraction of forces to motion of motionlees object m is mass of motionless object
  12. t'c/(c2 - v2)1/2 = t t2=t'2c2/(c2-v2) t2=t'2c2/(c2-dx2/t2) t'2c2/(t2c2-dx2)=1 t'2c2=t2c2-dx2 t'2c2/c2+dx2/c2=t2 t2=dx2/c2+t'2 t=(dx2/c2+t'2)1/2 We can not use the equation for solve of my task because we should know more data I am wrong there.
  13. You can measure short distance by ruler, then you can define dx. Scientists can measure large dx of light by brightness of supernova. Then speed of travel=0
  14. We can use variables dx is distance between the planets t1 is time of start of travel t2 is time of end of travel t' is time of traveling clock at end of travel t2 - t1 =(( dx)2/c2 +t'2)1/2 We need to define t1 t1=t2 - ((dx)2/c2 + t'2)1/2 Forces exist in mass. Mass can not exist without forces.
  15. Let's solve such task: We know distance between the Earth and green planet. Green traveler turned on its clock at start of travel to us. The traveler was traveling at different and unknown speeds. Time of start of the travel is unknown and we should define it. The green traveler has errieved to us and showed time of traveling clock. I can simply solve the task using my equation. Can you solve the task simpler?
  16. Clock correctly shows time only then when their motion of arrows and mechanism counteraction to the motion correspond to my formula. t' is time of traveler q is not Newtonian inertia. Unit of q is second, maybe quantum phisicits will create another unit. Energy should travel at c without forces counteraction. We can define change of distance without known time.
  17. t = ((dx)2/c2+q2)1/2 t is time dx is quantity of motion c is velocity of light q is quantity of counteraction of forces to motion q = t' for traveling object
  18. The small planet gets additional escaping momentum. It means that the big planet or the star get negotive momentum. It means the big planet or star get less energy than the small planet, but they don't lose energy. Were do the energies come from?
  19. I am wrong there. Let's concider next experiment: Big planet ,approuching to star, can trow away small planet. The small planet gets energy of escaping. Does the big planet lose the same energy?
  20. Escape velosity between center and surface exists. We can see contracted distance and slowed time, but we can not see change of distance because center and surface have general acceleration, wich compensates redusing or increasing distance by gamma factor due to acceleration. We can define the acceleration: Change of distance due to escape velosity= r - vet Change of distance due to acceleration= r- r/gamma r - vet=r- r/gamma gamma= r/(vet) t= 1 second therefore r/ve= 1/(1- a2/c2)1/2 a= (r2- ve2)1/2 c/r
  21. Also any field is ability to take energy from space and to return it back.
  22. Your body feels any stretching, only your brain doesn't.
  23. Freefalling person feels force of stretching because lower part of body tryes to fall faster, also length of body tryes to stretch it at acceleration like in Bell's spaceship experiment.
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