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Rob McEachern

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  1. Not anymore. In twenty-first century physics, they have become accepted without ANY experimental evidence: "There is no more experimental evidence for some of the theories described in this book than there is for astrology, but we believe them because they are consistent with theories that have survived testing." Stephan Hawking, "The Universe in a Nutshell", Bantam Books, 2001, pp 103-104. “Sabine Hossenfelder argues, we have not seen a major breakthrough in the foundations of physics for more than four decades… The belief in beauty has become so dogmatic that it now conflicts w
  2. It would be very interesting if it were actually true. But it is not. The most fundamental loophole of all, can never be closed, not even in principle; because strange correlations MUST exist, whenever two or more measurements are EVER even attempted on an entity, that only enables one (an entity that only manifests a single bit of information). For a more detailed explanation of this ultimate loophole, see http://vixra.org/pdf/1804.0123v1.pdf
  3. Thermodynamics. That is where Fourier analysis originated. There is no wave function in any problem. The use of the term "wave" is a misnomer. The structure of Schrodinger's wave equation is unlike that of the classical wave equation. But it is identical to the classical heat equation; it would have been more appropriate to call it the Schrodinger heat equation, describing a process similar to heat-flow, rather than wave propagation.
  4. Any experiment in which a multi-channel detector, responds to a mono-energy input (quanta) within each individual channel. That is what every Fourier transform's power spectrum describes. Thus, since wave-functions are mathematically described via Fourier transforms, it is true of every wave-function, whenever each "bin" in the transform receives only entities (quanta) with a single energy, Ephoton ,which may differ from one channel to the next. That is the origin of the Born rule. It happens with every experiment, that can be described mathematically via a Fourier transform's power sp
  5. Probability and energy density are related. Whenever the energy arrives within a detector, in equal quanta of energy, then the number of quanta detected by any given detector, can be inferred, from the ratio of total energy detected, divided by the energy per quanta. This fact is independent of the nature of the quanta; the debate about particle vs. wave is irrelevant. All that matters is that the quanta have equal energy. Which is why the experiments are always designed to ensure that is the case.
  6. I already have. See below. By the way I am not so young anymore either; Been there, done that. No ramblings are involved. I previously provided links to both a "much better defined", line-by-line computer demonstration, together with a paper that describes it, that falsifies Bell's claim and all the existing claims for "loop-hole free" Bell tests (by actually constructing classical entities, that falsify the most fundamental, unrecognized assumption of all, namely that there is "something else to measure" after the first measurement has been completed). Anyone can reproduce the
  7. On Challenging Science, particularly Physics, You have my sympathy Reg. Most living, theoretical physicists have yet to recognize (even though the long-dead masters, like Einstein and Schrodinger, repeatedly warned them about it) that they have fallen victim to the very problem noted in studiot's quote. Fools rush in, where wiser men have feared to tread. When you attempt to "measure something else", that your theory suggests exists, but that does not in fact actually exist in nature, then your theory "offers little" (though a little may nevertheless be a lot better than nothing). As I
  8. Feeling the need to eat and feeling hungry are two very different things, for those dealing with frequent low blood glucose levels. It is not low blood sugar that makes you feel hungry. For example, a type-1 diabetic may feel absolutely bloated and stuffed after finishing a large meal, but still have a dangerously low (and still plummeting) blood glucose level, as the result of a fast-acting insulin injection, which may enter the system, before almost any of the previously consumed food has. Pure glucose gels and tablets, when eaten, enter the blood stream much faster than other carbohydr
  9. It should be even more obvious, that if you change V, V will no longer be constant, as stipulated in the text book quotes, as the defining property of a free particle.
  10. Yes it is. E= (Kinetic energy + Potential energy) = (K+V). So (E - V) = K+V-V = K; the potential exactly cancels out in the special case, where V is a constant, regardless of what the value of the constant is. Note also that, given the expression for p, p2/2m = (E-V) = K = mv2/2, just as one would expect, for a free particle with only kinetic energy. The momentum cannot change if the particle is free.
  11. Of course - because the potential has no effect, thus, the particle is free. Here is a quote from Merzbacher, "Quantum Mechanics", second edition, pages 80-81: .
  12. It is not possible. The solution that you gave and claimed; "Which I think is more useful as you can plug numbers into it." Is not a solution to Schrödinger's equation, if the energy changes. You will find the same thing in any other text book on the subject. The author of the text cited, was David Bohm - a rather highly regarded figure, in quantum theory.
  13. In the book, there is a two-step process to evaluate a square potential: (1) solve the equation when the potential is constant everywhere (Swansont's question), which is done in the first paragraph, and then (2) evaluate what happens when a second level is introduced. But, if there is no second level (as in the question that was asked), then all the rest of the book, after the first paragraph is irrelevant: There is no second level that is less than the first. Potential wells exist when there is a relative change in potential. The partial derivative of kx with respect to x, depe
  14. There can be no well, if the potential is constant everywhere; wells require more than one level of potential. Where there is a well, there can be no free particle. Nothing can change in the solution you gave, because, in the derivation of that solution, "k" was unwittingly assumed to be independent of both time and position.
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