The density of two liquids (A and B) is given as 1000 kg/m^{3} and 600 kg/m^{3}, respectively. The two liquids are mixed in a certain proportion and the density of the resulting liquid is 850 kg/m^{3}. How much of liquid B (in grams) does 1 kg of the mixture contain? Assume the volume of the two liquids is additive when mixed.

# Help me to find out Density problem.

### #1

Posted 3 February 2017 - 06:01 AM

### #2

Posted 3 February 2017 - 06:17 AM

You will need to show some attempt at answering this for anyone to help you. Where exactly are you stuck?

### #3

Posted 3 February 2017 - 12:23 PM

Cough, cough

Is this really how they teach it in your school?

Different problem. So no. This is just how I attempted to do it.

How far off was I?

"My good sir,

I feel the need to inform you that your argument has reached rock bottom and has proceeded to dig.

Good day."

### #4

Posted 3 February 2017 - 12:33 PM

Different problem. So no. This is just how I attempted to do it.

How far off was I?

How about reading what HyperV wrote? Duh!

Education, like life, is a journey not a destination

### #5

Posted 3 February 2017 - 12:38 PM

How about reading what HyperV wrote? Duh!

To which he hasn't replied. So I tried to answer it.

"My good sir,

I feel the need to inform you that your argument has reached rock bottom and has proceeded to dig.

Good day."

### #6

Posted 3 February 2017 - 02:00 PM

To which he hasn't replied. So I tried to answer it.

It's only 6 hours since the OP wrote. as of your post. It's F-ked anyway, Everyone's answering it.

Education, like life, is a journey not a destination

### #7

Posted 4 February 2017 - 12:03 AM

**Moderator Note**

Since my last note was an unofficial probe as a moderator, I'm just going to come back and make this clear.**This is a homework HELP forum, not a we'll do your homework for you forum. **I had thought I had made that abundantly clear in my initial post, but apparently not. The OP was made not even a day ago. They might not have had a chance to log back on yet. Whatever the case, it would be greatly appreciated if you could all refrain from just giving out answers. Doing so helps absolutely no one, least of all the OP.

I have hidden the offending posts.

### #8

Posted 6 February 2017 - 06:53 AM

First, let *V _{A}* represent the volume of liquid A, and let

*V*represent the volume of liquid B, in 1 kg of mixture. Then, 850x(

_{B}*V*+

_{A}*V*) = 1 kg (of mixture). In addition, 1000

_{B}*V*+600

_{A}*V*= 1 kg (of mixture). We have here two equations with two unknowns (

_{B}*V*and

_{A}*V*). Solve for

_{B}*V*. The mass of liquid B in 1 kg of mixture is 600

_{B}*V*, which is equal to 264.7 grams.

_{B}### #9

Posted 6 February 2017 - 06:56 AM

First, let

Vrepresent the volume of liquid A, and let_{A}Vrepresent the volume of liquid B, in 1 kg of mixture. Then, 850x(_{B}V+_{A}V) = 1 kg (of mixture). In addition, 1000_{B}V+600_{A}V= 1 kg (of mixture). We have here two equations with two unknowns (_{B}Vand_{A}V). Solve for_{B}V. The mass of liquid B in 1 kg of mixture is 600_{B}V, which is equal to 264.7 grams._{B}

Thank you AshBox. I find the perfect solution.

### #10

Posted 6 February 2017 - 08:15 AM

First, let

Vrepresent the volume of liquid A, and let_{A}Vrepresent the volume of liquid B, in 1 kg of mixture. Then, 850x(_{B}V+_{A}V) = 1 kg (of mixture). In addition, 1000_{B}V+600_{A}V= 1 kg (of mixture). We have here two equations with two unknowns (_{B}Vand_{A}V). Solve for_{B}V. The mass of liquid B in 1 kg of mixture is 600_{B}V, which is equal to 264.7 grams._{B}

Doesn't a modnote mean anything?

Education, like life, is a journey not a destination

#### 0 user(s) are reading this topic

0 members, 0 guests, 0 anonymous users