E=mc^2

 

Apparently this can be used for code purposes in creating a set of numbers .  This and several other specific designs !

 

If we take a four letter word and assign a value proportional to the number of the letter in the alphabet , we can create a set of values  by placing the numbers in a c formation .  

 

In example the word scam , values of 19 , 3, 1  and 13.  Now if we place these values in a c formation , we can x reference or by variations define a specific set of values . 

 

In the word scam in a c formation we can use a x alignment to create two values ,  3+13 and 19+1 to give the 2 values !

 

NUMBERS ! 

 

 

 

 

 

1 hour ago, Numbers said:

E=mc^2

 

Apparently this can be used for code purposes in creating a set of numbers .  This and several other specific designs !

 

If we take a four letter word and assign a value proportional to the number of the letter in the alphabet , we can create a set of values  by placing the numbers in a c formation .  

 

In example the word scam , values of 19 , 3, 1  and 13.  Now if we place these values in a c formation , we can x reference or by variations define a specific set of values . 

 

In the word scam in a c formation we can use a x alignment to create two values ,  3+13 and 19+1 to give the 2 values !

 

NUMBERS ! 

 

 

 

 

 

19 + 1 = 20 and 3 + 13 = 16

So the codified version of scam is 2016?

 

Better question, how can you decode that?

 

If we have 26 characters in alphabet (a-z) and no other characters, we could pack word to single number, using formula:

[math]\sum\limits_{n=0}^{n<m} x_n*26^n[/math]

Character a = 0, .... , z = 25

Word consisting of { x₀, x₁, ..... x_n-1 }

Quantity of characters-letters is 26, therefor powering e.g. 26^1 gives completely unused area than previous 26^0, etc. where we can store the next letter of word, etc. with other powers (positive integer n>=0)

ASCII (8 bits per char) text is equivalent to:

[math]\sum\limits_{n=0}^{n<m} x_n*256^n[/math]

Unicode (16 bits per char) text is equivalent to:

[math]\sum\limits_{n=0}^{n<m} x_n*65536^n[/math]

 

Extraction of characters from such packed number can be done using pseudo-code:

Number x; // initialize it
while( x > 0 ) {
   int chr = x % 26;
   printf( "%c", chr + 'a' );
   x /= 26;
}

 

 

Edited November 23, 20196 yr by Sensei

7 hours ago, Numbers said:

we can create a set of values  by placing the numbers in a c formation .  

What is a “c formation”?

7 hours ago, Numbers said:

we can x reference or by variations define a specific set of values . 

What does this mean? How exactly do you cross reference?

7 hours ago, Numbers said:

In the word scam in a c formation we can use a x alignment to create two values ,  3+13 and 19+1 to give the 2 values !

There are a very large number of ways of generating the numbers 16 and 20 so it seems impossible to decode the word

7 hours ago, Numbers said:

E=mc^2

You do t use this anywhere so why mention it?