ydoaPs Posted February 25, 2018 Share Posted February 25, 2018 x^2 = x + x + ... + x (x times) d/dx x^2 = d/dx [x + x + ... + x] 2x = x 2 = 1 Enjoy. Now, can you find the problem? Link to comment Share on other sites More sharing options...
Raider5678 Posted February 25, 2018 Share Posted February 25, 2018 Yes. 2 = 1 is false. If you take x from both sides, you get: 2 = 0 So it should be proving 2 = 0, not 2 = 1. Link to comment Share on other sites More sharing options...
studiot Posted February 25, 2018 Share Posted February 25, 2018 1 hour ago, ydoaPs said: frax{d}{dx} Is this bit at fault? Link to comment Share on other sites More sharing options...
ydoaPs Posted February 25, 2018 Author Share Posted February 25, 2018 12 minutes ago, studiot said: Is this bit at fault? Yeah, as far as I can tell, it's because x is being treated like a constant instead of a function on the right hand side in the first step. Link to comment Share on other sites More sharing options...
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