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Cooper is more likely if you want to bend it with your hands. I have taken welding course in high school, and I used heat to bend metals to varies of shapes. Trust me, if you want your metal to be strong enough to carry 5 to 8 kg, then you could use little of heat or a bendable machine to bend the rod.

Today, I rather got in an arguement with my math teacher. We did geometric sequence review today, where she gave us this formula: [math]t_{n}=ar^{n-1}[/math] where a = first term, and n = any number. The question was: How long will it take for the population of the town to double? (Note: the first term is 26,235 and the rate is .09% which is 1.009 to signify growth.) My answer was: [math]52,470 = 26,235(1.009)^{n}[/math] [math]\log_{1.009}{2}=n[/math] [math]n=77.36240945[/math] or rather 77. My teacher answer was: [math]52,470 = 26,235(1.009)^{n-1}[/math] [math]n = 78[/math] (Note: Her answer was rounded up form 78.362...) I agrued that her answer was wrong, because I checked the graphic calcular, and I input my answer of 77.36240945, and it yielded 52,470. So who do you think is correct? Because [math]t_{n}=ar^{n-1}[/math] is rather a geometric sequence formula, not a real life formula like mine. Let me know.

Now, I'm sure nobody want a mathematician thread anymore?

I recieved a semanir at DAL (Dalhousie University in Halfiax) long time ago, and it provdied the 9-joining-dots problem. It's a good problem to show critical thinking, and the structure of the question. What I meant is, by the definition of "line". If it only said "line", then the line can be wavy, curvy, straight, whatever you think. Although, the question said "straight lines". The point is that you always have to read the questions carefully.

Very true AzurePhoenix. I known a woman who have been aborted three times in her teenager years, and now she is an elderly woman, and she went into a deep physical and emotional depression. It looks like she is going to kill herself any minute. It's not funny at all.

Are you talking about the axis of symmetry? If so, it's the line middle of a parabola. e.g. [math]x^{2}-4x+2[/math] Axis of symmetry is [math]x=2[/math].

Can anybody answer post #69?

Anyone who can help me here? What is the difference between [math]\sum_{n=1}^{\infty}[/math] and [math]\sum_{n=1}^{n}[/math]? My teacher said that the "n" means any number, and the infinity means forever. What's the difference?

The answer for [math]\sum_{n=4}^{10}(3n-3) - \sum_{n=5}^{10}(3n-3)[/math] is [math]9[/math]. Is this correct?

(m)(17) I am an anti-abortionist. I'm a catholic person and God wishes us to love children, because he made us. Imagine if it was yourself as the baby, and you get killed for no reason. That's not right.

The solutions for the Rubik's Cube is not infinite. You can create a statistical information where you can represent the colours by a number. Thus, you'll create matrices and you need to use linear algerba to find out whatever you need. But, I assure you that there will be thousands of matrices. That is my guess.

You have a limitation of upload pictures on SFN. I think around 1,200 KB.

I looked in the dictionary for "parapsychology". It said, "The study of the evidence for psychological phenomena, such as telepathy, clairvoyance, and psychokinesis, that are inexplicable by science". I don't see any point of discussing this, if it's "inexplicable by science". But to be frankly honest, I wish we do have teleporter, so I can travel to distant places very quickly.

Do any of you guys watch the show, "Surface"? It's a good television show that is solely largely on cloning. I watched every episode, and it's actually very fascinating.

I am curious... how much does the 10Ghz Intel processors cost?

I am starting to running out of questions on the Fermat booklet that are challenged enough for you guys.. Next Question: The arithmetic sequence, a, a+2d, a+3d,...,a+(n-1)d has the following properties: -When the first, third, and fifth, and so on terms are added, up to and including the last term, the sum is 320. -When the first, fourth, seventh, and so on, terms are added, up to and including the last term, the sum is 224. What is the sum of the whole sequence?

It's nice to see other person's solution. You did it differently than I did it, as I used algerba to get my answer. For the 2 medium squares, I put in "y" for the sides, and "x" for the single big square. You notice that the left side's total length is 11 cm. Thus [math]x + y = 11[/math] for the opposite side. I changed it to [math]y = 11 - x[/math]. Now for the equality of both top and bottom length I got [math]5 + 2y = 6 + x[/math]. Hence: [math]5 + 2(11-x) = 6 + x[/math] [math]5 + 22 - 2x = 6 + x[/math] [math]27 = 6 + 3x[/math] [math]x = 7[/math] Therefore for the length of y:[math] y= 11 - (7)[/math] is 4. [math]7 + 6 + 11 + 5 + 8 + 4 + 7 = 48 cm[/math].

[ATTACH]1208[/ATTACH] Rectangle ABCD is made up of six squares. (Notice: my drawing is not good, as you can see ). The areas of two of the squares are shown. The perimeter of rectangle ABCD, in centimetres, is ? This problem shouldn't be a hassle for you guys.

Good job Connor. I'd appreciate your opinion on the cube question. I'll post a new question tomorrow.

That's why we need more inputs from the other SFN members to see who favour in my answer or yours, but nobody seems to participate except The Thing. Anyway, the answer of 168 kg is incorrect. Did I scare there for a second? Ha, no, it is actually correct, and we both know that. Next question: The lines [math]y = -2x + 8[/math] and [math]y = \frac{1}{2}x - 2[/math] meet at (4,0). The area of the triangle formed by these two lines and the line [math]x = -2[/math] is ?

My answer still remains at 58. I counted the right, left, and top to have 12 surface area units. Plus, the alone triangle at the bottom which is just 2. So the total surface areas of the faces is 38. 38 + 20.784060969 is 58.78460969. Those questions that I got was created by Waterloo University in Ontario so I don't have the answer for the questions. I have another question, but much easier to give you guys a break. You should answer it with no problem. The weight of a lioness is six times the weight of her female cub and four times the weight of her male cub. If the difference between the weights of the male and female cub is 14 kg, the weight of the lioness, in kg, is ?

What I meant was that when you cut the cube according to the lines, you won't cut the verticles. Therefore it leaves a small triangle, which should be 4 corners for each piece. That's my theory.

I couldn't find the hexagon formula on the Internet before I saw it on your last post, and I used it and calculated the area of the hexagon. I got [math]20.78460969[/math] too. However, I don't agree with your addition of the faces. Let's look at a different perspective: A normal cube have 8 corners right? Well, when it's cutted, each piece should have 4 corners. It's sure is hard to imagine the cube being already cut. It would definetly be easier if I had a real cube model and cut it to see it more clearly.

I'm looking for more participation from other SFN members than just you. You only want to figure out the surface area for a half piece of the cutted cube. I found the center line of the hexagon to be [math]\sqrt{32}[/math], and all the edges to be [math]\sqrt{8}[/math], from using the pythagroem theorem: [math]\sqrt{2^{2} + 2^{2}} = \sqrt{8}[/math]. (But I don't think this measure is really necessary to know). I figured out the surface area of the hexagon to be 14.627417. Plus the 3 surfaces with 14 units. (They are not 16 units anymore because the cut caused 3 small areas to be with the other half). 14.627417 + 14 + 14 + 14 = 56.627417. The offered multiple choices are: (A) 69 (B) 48 © 32 (D) 65 (E) 58 So obviously my answer is the closest to (E). Do you guys agree with my answer or not?

I don't understand your question.