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I don't like professors who are brain bullies. Do you know what "brain bully" means? It means that the professors are using big words, complex concepts, and figures in their lectures. They think it will make them look smarter. Instead, a good professor would know who his/her audience is, and give materials that we can understand with what we already know. Also, innovative exhibitions are usually very nice.

Since Martin has claimed the Alfred E. Neuman avatar before me, I have changed my avatar. The gentleman in my avatar is Johnny Depp acting as Ichabod Crane in "Sleepy Hollow". The only reason I got it is because I saw the movie awhile ago, and it's one of the most freakiest bloody movie I have ever seen. Nobody told me how to resolve my smudges when I view LaTeX scribbles?

Hello buddies!! It has been since June 12, 2006 that I have posted on SFN!! I have been doing good, as I'm taking Mechanical Engineering at University of New Brunswick. (In New Brunswick, Canada). It is keeping me really busy, as I just finished my midterms, but I love it. I also noticed that LaTeX appears as smudges on my laptop. Any resolution(s) to remove it? Thanks and hope to hear from you guys again!

Though I have done this launcher project a month ago, I want to give you guys an update. My partner and I made a hortionzal launcher on top of a table. Who said that we had to make an angled launcher? Most of our classmates made that way, and their eggs broke. Our launcher was successful since the egg arrived in a cup that is 3 cm in diameter! We didn't have to pass in our lab reports and recieved 100% on it automactially.

I can't seem to find a way to solve for x: [math]x^3 + x^2 -6[/math]. I know the answer is 1.54... but I don't know how to get it! It's frustrating!

Mind give me some examples? That would be helpful, thanks.

what's the difference between [math]\frac{d}{dy}[/math] and [math]\frac{dx}{dy}[/math]?

I have a laptop that have Windows 98 OS. Whenever I want to view pictures, I have to double-click and open the pictures to view them. Then close the window, and click another picture, and so on. It's a long process comparing to Windows ME or Windows XP. Windows XP have thumbnails where you can see all the pictures automactically. I was wondering if there's any program for Windows 98, so I can see the thumbnails, or is there any program that will allow slideshow, or picture viewer? Thanks guys.

[math]\frac{1}{\frac{3}{3}-\frac{1}{3}}[/math] = [math]\frac{1}{\frac{2}{3}}[/math] = [math]1 \cdot \frac{3}{2}[/math] = [math]\frac{3}{2}[/math] For example: [math]\lim_{x\to\infty}\frac{x^2}{x^3 + 2x - 5} = \infty[/math] Nope, not before you mentioned it. I googled for l'hopital's rule and it appears that [math]\lim\frac{f(x)}{g(x)} = \lim \frac{f'(x)}{g'(x)}[/math] is in the works. It said, "This is a great lesson whose relevance goes way beyond math. L'Hospital's rule is not for finding limits. It's just a statement about functions and their derivatives, and it doesn't care what you want to prove."

so I assume a to be the first term; r = rate; and k is the exponent. Using [math]\frac{a}{1-r}[/math], I got [math]\frac{1}{1-\frac{1}{3}}[/math] which comes to [math]\frac{1}{.667}[/math]. Remember calculator wasn't allowed so I have to leave the answer at that. The answer would be 1.5. For [math]\lim_{n\to2}\frac{x-2}{x^2 - 4x +4}[/math], limit doesn't exist. Does that mean there is no limit as in "undefined"? Solution: [math]\frac{x-2}{(x-2)(x-2)}[/math] = [math]\frac{1}{x-2}[/math] = [math]\frac{1}{0}[/math]. The limit doesn't "exist" or "undefined", right? How about this one? [math]\lim_{n\to0}\frac{\sqrt{1+x} - 1}{x^2}[/math] You input the zero and you get [math]\frac{0}{0}[/math]. The limit for this one doesn't exist neither. Is that right?

Yup, I just noticed that in my textbook. I have to find the distance that runs toward the Venus's centre, and add it to the distance "above the surface". Thanks.

I want to do the questions 'cause I want to. Did you read post #1? It's the practice exam from UNB to get yourself ready for Calculus for the first year of University. I don't have any notes on some of the questions, but I got to admit that I do have a Calculus textbook that I can look in. I'm just too lazy to look around in the textbook, or even search on the internet. I'll try to do that next time. For the geometric limit above, I got limit of 1.5 for the answer. I used calculator though, and that wasn't allowed. I'll look in the textbook. In post # 7, what does "a", "k" and "r" mean though?

All right thanks.

That's not a nice thing to say. I'm deaf myself so English is my second language, and I had to look in the dictionary to look up for "converge". I have to put "yes" or "no" for the limit questions. So if it does have a finite limit, I put in "yes"? Plus, I have never learnt how to do geometric limit. That's why I'm asking you guys... I do know how to do a finite summation, but not infinity. Any help please?

I could send you my grade 11 chemistry notes

What's the difference between the formula of [math]g = \frac{F_g}{m}[/math] and [math]abs(g) = G\frac{m}{r^2}[/math]? Note: abs(g) means absolute value. I don't know the latex code to input absolute. Because the question asked me: Calculate the gravitational field intensity 340 km above the planet Venus. I used the second formula above, where r = 340,000 m; G = 6.67 x 10^-11; m = 4.83 x 10^24 kg. I got [math]2786.859862 \frac{N}{kg}[/math] for the answer. Is this correct? I still don't know why I used the second formula, not the first one, though?

Right I got it. For the limit of [math]\sum^{n}_{k=0}(\frac{1}{3})^k[/math] where n = infinity, I got the answer of zero. Is this correct? What does "Does the sequence converge to a finite limit as n = infinity" means? (It's for the limit questions). Another question: Find all the real solutions of the equation [math]\sqrt{5x-1} + 2x = 1[/math]. I got the answer of [math]\frac{1}{4}[/math]. Is this correct?

The limit occurs when n -> infinity. [math]\frac{(n+1)}{(n+1)(n+1)}[/math] therefore giving you [math]n+1[/math]. So there is discontinuity at -1. So the limit is zero?

I'm establishing this thread to ask all the questions that I'm having problem with, or to make sure my answer is correct. The practice exam is at http://www.math.unb.ca/~maureen/UMRA/Test2005.pdf and it don't provide the answers to the questions. So the sole purpose of this thread is to make sure my answers are correct, or I need some help with some of the questions. NOTE: NO CALCULATORS! The limit of [math]\frac{n+1}{n^2 + 2n + 1}[/math] is undefined. Is this correct? What is the limit of [math]\sum^{n}_{k=0}(\frac{1}{3})^k[/math]? How do I sketch a graph that satisfies the equation of [math]2^y = x[/math]? How do I put it in y form? These are some of the questions to start. I'll have more for later.

I drew a FBD (Free Body Diagram), and [math]F_N[/math] points to the north, because the person is standing inside the rotor-ride. As [math]F_N[/math] points to the north, [math]F_g[/math] points to the south, and [math]F_a[/math] points toward to the center of the circle. I have a question: Does both [math]F_c[/math] and [math]F_a[/math] points toward the center of the center? Another question: Is it really necessary to put negative sign for the gravity? I know it points down, but sometimes, it's not required to put negative sign all the time. At least, what I have seen so far in my Physics class.

Yes, right.

In a "Rotor-ride" at a carnival, riders are pressed against the inside wall of a vertical cylinder 2.0 m in radius rotating 1.1 revolutions per sec when the floor drops out. What minimum coefficent of friction is needed so a person would not slip out? Collecting the information from the question: [math]f = 1.1[/math] [math]r = 2.0 m[/math] [math]\mu = ?[/math] First, I used this formula: [math]a_c = 4\pi^2rf^2[/math] and it yielded [math] 95.5377706 m/s^2[/math]. To find the velocity you use: [math]v = \frac{2\pi2}{T}[/math]. Therefore, you need the value of [math]T[/math]. [math]T=\frac{1}{f}[/math], yielded [math]13.82300768 m/s[/math]. Next step, I know this is wrong, because [math]\mu[/math] can't be over 1. What I did: [math]F_f = F_c[/math] [math]\mu = \frac{v^2}{rg}[/math] [math]\mu = 9.738814536[/math] Can anyone tell me what I did wrong? And how to continue the solving, because I know that you need [math]F_f[/math] to be greater than [math]F_c[/math], so the person won't drop through the floor.

I am having a problem here. I can't figure this out. [math]y=(3x-2)^4[/math] is [math]81x^4 - 216x^3 + 198x^2 - 96x + 16[/math]. The derivative for the above function is [math]y\prime = 12(3x-2)^3[/math]. The question is asking me to find out the pattern and write it is as an equation in the same form of the power rule. ([math]y=ax^n[/math] is [math]y\prime = anx^{n-1}[/math]). This goes same for [math]y=(2x^2 + 3)^5[/math] which is [math]y\prime = 20x(2x^2 + 3)^4[/math]. I got [math]y=(ax+p)^n[/math] and [math]y\prime = an(ax+p)^{n-1}[/math], which worked for the first function, but not the second. My teacher said that for the second function, "You know that 2 x 2 x 5 is 20. How can you make [math](2x^2)(5)[/math] be 20x. You will need to take 2 derivatives." Do you guys know any equation that will fit both functions?

Given f(x)=1/x; e(x)=x^2 + 4; g(x)=x^3 Consider g(e(f(x))), f(e(g(x))), and e(f(g(x))). Question: Make an intelligent conjecture about the relationship between the range of a composite function and the exponential powers of the original functions. g(e(f(x))) and e(f(g(x))) is [math]\frac{1}{x^6}+4[/math]. f(e(g(x))) is [math]\frac{1}{x^6+4}[/math]. The question is asking to find the relationship between the range of a composite function and the exponential powers of the original functions. For instance: g(e(f(x))), e(f(g(x))), and f(e(g(x))) have an infinity range. The exponentials of the original functions are: -1, 2, and 3. I'm not sure how there is a relationship? I have no idea. Can anyone help me out here?

Yeah, I have done that. I was thinking maybe somehow I can make the egg land on its sharpest curve (bottom), then the egg won't break. But it's a problem, because you can't control the egg's flight. (rotations, flips, etc.)