# Arnav

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Space time
1. ## Millikan's oil drop experiment

Thank you studiot for the in depth explanation
2. ## Millikan's oil drop experiment

Could you please elaborate what do u mean by "charge"? I mean, are u refering to "kind of charge(+ or -) on the droplets"? One of my ideas is this: The oil droplets caught both - and + charges,(some caught only -, some only +, while some both). Millikan knew how he had arranged the electrodes in the apparatus and how positive and negative charges would interact with them. If the charge on a droplet was net +, it would accelerate down when Electric field strength was increased while it would decelerate if it had net - charge. If it was neutral, there would be no effect.
3. ## Finding the range of a function

I was told to find the range of a function f(x) = (x²-1)/(x-1) where x cannot be 1. I know the proper solution is this : Since x cannot be 1, f(x) reduces to x+1 therefore Range = R - {2} Bu at my first attempt I did this: let y = (x²-1)/(x-1) yx - y = x²-1 x² - yx + y -1 =0 For x to be real, the discriminant of this equation should be >= 0 Therefore y² - 4(y-1) >= 0 (y-2)² >= 0 y can take all real values. Now, where did I go wrong? Why is 2 also coming in the range with the second method? How do I distinguish when
4. ## Millikan's oil drop experiment

In Millikan's oil drop experiment, when the oil droplets fell through the hole in the top plate, and passed through the ionised air, did only electrons get attached to the droplets? Or both the electrons and the cations? In my book, only electrons are shown as attached to the droplet. Why only electrons got stuck? Why not the positive ions as well? Or did they?
5. ## Error analysis through differentiation

I was required to do the error analysis for an experiment with the aim of finding the relative density of a body. In the experiment, the weight of the body in air war found to be w₁ = 8.00 +- 0.05 N while the weight of the body in water was found to be w₂ = 4.00 +- 0.05 N. Using the relation, ρ = weight in air / (weight in air - weight in water) where ρ denotes relative density, I did the error analysis as shown in the attachment. However, my friend did the error analysis as this: ρ = w₁/(w₁- w₂) Δρ/ρ = Δw₁/w₁ + Δ(w₁- w₂)/(w₁- w₂) Δρ/ρ(max)
6. ## Ionisation in radioactive decay of atoms

Oh ok I understood. Thanks !
7. ## Ionisation in radioactive decay of atoms

It definitely does! Thanks Hey cuthber, could you please elaborate what do you mean by this?
8. ## Ionisation in radioactive decay of atoms

There is a question, a satisfactory answer to which I haven't received for long. In alpha decay, the number of protons in the parent atom decreases by two while the number of electrons in the atom remains same. Does the parent atom on undergoing alpha decay convert into an anion? In the same way, in beta minus decay, the following transformation takes place : ₀¹n ----> ₁¹p + e⁻ + v̅ the proton remains in the nucleus and electron and the antineutrino are ejected. From this, one could conclude that the positive charge on the atom increases by
9. ## Voltmeter and its resistance

Thanks guys for taking out your time and answering my doubt. Sorry I've been a little too inactive
10. ## Voltmeter and its resistance

Sorry, but I haven't been taught about potential dividers yet. Yeah, I reckon in an actual circuit the number of resistors would be more than 1, as my case of "cell with 0 internal resistance and only one load" is very very ideal. So in a non-ideal case, even if we ignore the internal resistance of the source, the voltage measured by voltmeter would again come out to be less if its resistance is not very very high. I have uploaded 3 scenarios, one which is the actual case, one with low resistance voltmeter, and one with very high resistance voltmeter. I have ignored interna
11. ## Voltmeter and its resistance

A voltmeter has a very high resistance so that it doesn't draw a considerable amount of current from the circuit when connected in parallel. Lets say we have a circuit consisting of a single cell and a load of resistance R. Now a voltmeter is connected in parallel with a load of resistance R. If the resistance of the voltmeter will be low, then it will draw some current from the circuit , leading to an increased magnitude of current in the circuit than before( or we can say equivalent resistance of the combination would be less than before, leading to increased current). If the cell has a

Thanks swansont for the paper, but I lost it at the caloric thing😅 Studiot, how did Avogadro conclude that the ratio of the volumes of two gases under similar conditions was equal to the ratio of their molecular weights? Sorry if I sound too dumb

How did Avogadro 'actually' derive his law stating "equal volumes of gases under similar conditions of temperature and pressure contain same number of molecules" ? I am a 10th grader so I would appreciate a lucid and intuitive explain if the derivation involves higher concepts of science.
14. ## Internal resistance of a cell

Thank you for your reply studiot, but I couldn't follow the second last paragraph of your explanation, starting with Your book must have assumed.... You see guys, even here I am getting mixed answers, John says the data is insufficient and studiot says the question's fine.
15. ## Internal resistance of a cell

Here's a question, and my doubt is at the end of the question. I have been struggling with this doubt for quite long and have been receiving mixed opinions. A cell of emf 12 v supplies a current of 400 mA to an appliance. After some time the current reduces to 320 mA and the appliance stops working. Find the resistance of the appliance, the terminal voltage of the battery when the appliance stops working, and the internal resistance of the cell. In my book, the answer to this ques is given as follows: 1. Given, emf = 12 volt, I = 0.4
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