chenbeier

You got it.

The question is why cyanide is used and not only hydroxide. I guess chlorine is exchanged by cyanide and in a further reaction the nitrile will react with the alcohol group to form a ring. Look for Pinner reaction.

Contacts normaly coated by gold,tin, or other noble metal, there will be no oxidation. Copper ones have to be cleaned time to time by special contact spray, but dont put anti tarnish on it. It will work like a resistor and the contact will not work probably.

No, both salts have good solubility. You will have Ca2+, Na+, CH3COO- and Cl- Ions in the solution.

The Manganese-IV-oxide is reduced to manganese-II,III-oxide Mn3O4

Decomposition startes above 65 ° C and the best performance is 270°C and it needs 950 kJ/ mol

Yes correct.

Thats correct, for calculating the conversion of the given mass. But the head line asked for decomposition temperature. So different questions.

Temperatures above 680°C decomposition starts. Save reaction is at 900° C. In industrical oven it's used 1000 - 1300 °C.

Again dont answer 2 year old threads

Dont post answers for 3 year old threads, probably the people not more alive.

Citroc acid is a Solid compound, if the water is ebaporated then you get a white residue. To avoid change to acetic acid.

1,3 g/l Na2CO3 corresponds only to 0,05 % CO2.

To make it fester boil it.

Calciumchloride will absorb water until it changes to liquid. So probably not good idea to use it and blow air over it.

Yeah that is the correction of the observers1 question.

No, CuSO4 dissociates to Cu(H2O)4 2+ ( blue colour) and SO4 2- ions, like all salts do if dissolved in water. NaCl => Na+ + Cl- as example. And your equation is wrong. H2O + CuSO4 ---> H2SO4+ Cu? You forget the oxygen from H2O H2O + CuSO4 <--- H2SO4+ CuO is a reaction what can take place.

Put some Gallium to a Piece of Aluminium and watch after one week.

No, but english is not my mother language. I corrected it .

https://www.nobelprize.org/prizes/chemistry/2022/summary/

To get the Anode and cathode activ it needs charging and discharging. No use will get residius on the electrodes. Strong use charging and discharging also minimize the lifetime by dissolving of the electrodes. The longest lifetime is achieved to have small discharging and charging current. For this you can buy small rectifier to do this job, voltage controlled.

This topic I on the border limit to discuss. Not so much hints about how explosives reacting please. This topic should be closed.

You are right,if it is E2. I was thinking it is E1.

The first molecule will be built because after Elimination the Cl. The carbanion is stabilized through the methyl group.

Your photo, I cannot open. 404 file not found on unbuntuu