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About DandelionTheory

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  1. I found it through Google search: https://www.google.com/url?sa=t&source=web&rct=j&url=https://web5.uottawa.ca/www10/every_2012/document/20120404083003001.pdf&ved=2ahUKEwi7muHPhpjrAhXkLX0KHY5QCyoQFjAfegQIBxAB&usg=AOvVaw3_RHdoHQ4dwiVhXQq_5FB9 Thank you. Do you know what direction I would need to go to find that out?
  2. Oh, haha. That too. I'm not calculating current increase, the question is: does the magnetic field increase due to current increase maintaining the spark gap, and does that additional current increase in the spark gap translate to force on the wires? I'm heavily leaning on current due to this
  3. In the original scenario, the wires are bent away from each other; up is also a direction the wires are forced. This was in reference to the picture strange posted. Agreed. The initial spark is a factor of humidity, voltage, atmosphere pressure, dielectric breakdown, and some more. From what I've learned about Jacobs ladder papers, the current supplied maintains the arc. Perfect. That's the answer. But "forced away from the center of the current loop" is more specific. If the initial arc is at shortest path, maintain arc with increased current, which increases magnetic field and displaces arc and current in wires. When arc's contact with the ground wire reaches the length of the ground wire, disengage current supplied and calculate total displacement. I cannot assume further if this isn't agreed upon as the intent of the op.
  4. The current in each rail acts on the armature and the opposite rail. The circuit is completed by the armature in a rail gun. in the scenario I presented, the thermionic emission, aka electric arc, substitutes the armature. This would complete the circuit right? Arc and wires would move perpendicular to magnetic field. Rail guns work this way, if the current is in flux over time. When the arc reaches a point past the bounds of the box, the wires have moved while the arc can return to the battery. I would assume this can be repeated. The original scenario had the wires bent away from each other because I assumed the arc would take the shortest path and would be forced downward away from the center of the current loop while the current in the wires would be forced away from the center of the current loop at each given slice of time.
  5. I said "In this scenario, the positive wire's exposed end is 1mm from the closest end of the negative blue wire. The electric field applied is over 3kv to exploit thermionic emission, and induce a spark." As a physicist, what additional information is required for the scenario to be understood? I do not see external fields on rail guns.
  6. This is a question about variables having to do with force on a current. I need correction in my understanding, I don't get the difference when a current is in a wire vs not. I have drawn out a scenario, the contraption I drew consists of 5 parts. The positive wire (red), it's insolation with exposure at one end (black), the connecting structure (green), the negative pole(blue), and a power source (inside green). In this scenario, the positive wire's exposed end is 1mm from the closest end of the negative blue wire. The electric field applied is over 3kv to exploit thermionic emission, and induce a spark. If the current was to increase during thermionic emission, would the changing magnetic field push all current away from the center of the current loop?
  7. "and are the forces between the currents in the wires repulsive or attractive?" my speculation.
  8. if i set up a wire loop J with a current I flowing clockwise, and attach wires AB, BC, CD & DG as seen in the picture the current on wires AB, BC, CD & DG i would expect to be 0.5I while the portion of loop J (portion AC and CG of wire loop J)adjacent to wires AB, BC, CD & DG also carries 0.5I my question: are the forces between the current in each wire and current loop J attractive to each other? and are the forces between the currents in the wires repulsive or attractive?
  9. Condescension does not promote confidence. pretend i know the basics about inline masses.
  10. Can we agree my example has nothing inline masses? Right angles buddy Also read the part about rigid connection mentioned, seems you think C would "move closer" to A regardless of the rigid body between them. Am I correct to assume you forgot it wasn't a rope?
  11. How do I do it? If you take out mass A entirely it's opposite still, if you take mass C out instead it's opposite.
  12. got you, so if i calculate over time i would need to account for this. i attempted to use variables in order of magnitude to help with this problem, also i add force at certain times due to the units being in newtons/kg
  13. F1 is done to mass A by mass B, F2 is the opposite reaction mass B feels, F3 is the opposite to F2 due to mass B & C being connected.
  14. may i ask if this partains to the slight thousandths of a unit distance the 3 weight system seem to do?
  15. if you have 3 masses A, B & C A & C are rigidly attached to each other B Pivots around C via a rigid bearing. If a force on any of these masses is to be represented correctly, opposite forces need to be shown for every force applied. so if mass A acts on Mass B(represented by F1 and F2), the work done on mass B will be done oppositely to Mass C (F3)correct? see picture below.
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