Homework Help

So hi! I can't access my other account since I can't login through facebook at the time so I created this other account. Hi Fellow scientists, I'm a grad student in Wildlife Science and I can't seem to wrap my head in building a phylogenetic tree involving multiple genera. It's not really an assignment but I am kinda falling behind in my class due to this. A help would be greatly appreciated! We had a similar thing in the lab class but this thing is similar to it as we try to list traits and determine their characters states across genera. My conclusion here is that Nyctixalus is the closest to the outgroup; therefore, more basal than the rest. What I start to have tr…

Concept If resonance energy is more that means the means resonance structures have varying energies and it should be less stable aka more energy ? So more resonance energy = More Stability ? Problem 8.16 Does the electron movement be of 1 electron and not a pair. C needs 4 more electrons the 2 hooked arrow shows C is getting 1 extra electron. Problem 8.17 Resonance structure needs to have same no. of unpaired electrons. Why charges develop of II Why is O in III +ve Explain “does not contribute as oxygen has positive charge and carbon has negative charge, hence least stable].” Problem 8.18 In II why would O develop +ve charge Explain the answer Electrometric Effect Book s…

It seems like a miss-print/render H+ is partially positive but still bonded ? Positive charge needs to be on C for it's empty p-orbital to be stabilized by adjacent C-H bon's sigma bond. What is the role of -ve charge on C ?

Ethyl is C2H6. Why why C2H5 is called that here ? Aniline means benzenamine (C₆H₅NH₂) but NH2 is at 1. So it can also be written as 1-amino-4-Ethyl-2-methybenzene ?

Example if carbon is bonds to 3 species we assume it's singly bonded with 2 and doubly bonded with 1 and has hybridization of sp2. Why don't we assume sp3 and there is a negative charge on C ? Is it role of hybridization is to form maximum sigma bonds ? All non-hybridized orbitals form pie bonds ?

In (a) Is the Pie bond of Double and Triple Bond CC different that is why written separately in answer

Carbon are 4 valence electrons and Oxygen has 6. So C being sextet is -2 charged ?

Example CH3CH2COCH2CH3 How do we know that CO has a double bond

Firstly there are what seems to be typos, H has negative charge the latter inverse equation are X instead of H in denominator. Question solubility is for individual ions for salt they is solubility product Ksp ? What is S [f S] and why that equalts to Ksp and S^2 {KS/(Ks + H)} and how is that equal to S = {Ksp (H + Ka) / KA}^1/2 I took me 2+ hours to try and understand this but still don't get it.

If yes what does this mean ? What would the graph look like ?

What makes me think this - Here RHS is substracted from both sides and x^2 terms are also combined. then both sides are multiplied by -1 that seems like cheating, just flipping signs.

Book says - "(f) Enthalpy of Dilution It is known that enthalpy of solution is the enthalpy change associated with the addition of a specified amount of solute to the specified amount of solvent at a constant temperature and pressure. This argument can be applied to any solvent with slight modification. Enthalpy change for dissolving one mole of gaseous hydrogen chloride in 10 mol of water can be represented by the following equation. For convenience we will use the symbol aq. for water HCl(g) + 10 aq. → HCl.10 aq. ∆H = –69.01 kJ / mol Let us consider the following set of enthalpy changes: (S-1) HCl(g) + 25 aq. → HCl.25 aq. ∆H = –72.03 kJ / mol (S-2) HCl(g) + 40 aq. → HC…

Yesterday was my periodic school test in science, and one of the questions asked: “What type of reaction occurs when fuel or gas burns?” I wrote "combustion reaction" as my answer, but the teacher marked it wrong and said the correct answer is "oxidation reaction." According to NCERT Class 10 Science, the main types of chemical reactions listed are: Combination Decomposition Displacement Double Displacement Oxidation Reduction (and Redox) While combustion isn't listed under the core classification, NCERT Chapter 6 (on combustion and flame) clearly defines combustion as a reaction where a substance combines with oxygen to release heat and light — i.e., exactly what happens…

Basically an object is being pulled by force of 150 N from both sides. The question asked to calculate magnitude of force? The question did not explicitly mentioned whether it is the net force or the total applied force. So I assumed it is the magnitude of total applied force 150 + 150 = 300 N Isthe answer correct as in the question it was not explicitly mentioned and I do know that net force is 0 N

I need help solving this, i tried copying the table but it got disfigured here, here is the link (https://en.openprof.com/wb/measurement_problem_2?ch=3903) to the question page to see it better "Complete the table: Physical quantity Quantity label Base unit Name of the base unit Measuring device time m …

What is position +sec x time

Hi - I'm struggling to understand the attached question from a take home lab. If anyone has suggestions, clarification, or explanation - I would greatly appreciate it. Thank you

Just wondering if anyone is able to help me with this biology question. When you get an infectious disease you may get a temperature. This is a way your body defends you as many microorganisms cannot reproduce at high temperatures. However, people always try to bring the temperature of an ill person down. Explain why this may be the case. (4marks) I have absolutely no idea where to start here..

So, I had thread. The thread was under some different account in mid 2024 when I was studying at Austin Peay college Tennnessee usa (because I know some viddyers of this site are in some backwater country and it's unfortunate that even with computer tech we can't universalize our tech due to foreign "computer science"). Anyhow, if you have a Galileo or a Newton in 2025, which you do, you'll have link to youtube channel removed still, hopefully. but the issue is that some arbitrary mod can shut me down instantly even though obviously I'm the only one with pre-decidedly accurate knowledge of AI. Real AI, not this shit about China being spewed by Trump. So go to trash c…

"An unmarked police car, traveling a constant 90km/h, is passed by a speeder traveling 140 km/h. Precisely 1.00 s after the speeder passes, the police man steps on the accelerator. If the police car's acceleration is 2.00 m/s^2, how much time elapses after the police car is passed until it overtakes the speeder (assumed moving at a constant speed)?" blew my mind away

Hello, I am an AP Research student at Texas. For reasons unknown, I decided to make my research project an online experiment involving children aged 8-12. This is really hard, given the need for the IRB, and the difficulty of distributing the experiment. Basically, children aged 8-12 will fill out a survey on age compression, watch 6 Instagram reels that are kid friendly, and then do the same survey, and I'll see if there is a quantifiable difference in the rating system of each question. I recognize now that it would be so much easier to do something like a metanalysis, or an experiment without human subjects, especially minors, but too late to back out now. My question …

Prove that groups of even order contain at least one element (which is not the identity) that squares to the identity. In case of a cyclic group, it is easy. Such group consists of {e, g, g2, g3, ..., gn-1} and contains element h = gn/2. This element, h2 = (gn/2)2 = gn = e. But how to prove it when the group is not cyclic? P.S. Oh, got it. Just count the pairs, element and its inverse.

I.e., show that A4 has a normal subgroup. I did it by brutal force and would like to know if there is a more elegant way. My solution: A4 consists of 4!/2=12 permutations: e = identity, 8 permutations of the kind (1 2 3)=(1 2)(2 3), (1 3 2)=(1 3)(3 2), etc., and 3 permutations with separated cycles: a = (1 2)(3 4) b = (1 3)(2 4) c = (1 4)(2 3) Because of the separation, the cycles in a, b, and c commute, and thus a2 = b2 = c2 = e. I've checked manually that ab = ba = c, ac = ca = b, and bc = cb = a. So, {e, a, b, c} is an abelian group. An abelian subgroup is normal. Thus, A4 is not simple. Let me know if an…