KeV, MeV and GeV....
Posted 19 January 2008 - 05:40 PM
for instance the annihilation energy of a Positron and an Electron is 511KeV.
well that`s Nice and everything but...
since I have these exact antimatter anihilations going on in my Lab 24/7, why am I not seeing 50+ inch arks every time it happens?
also, since 511KV is reasonably easy to attain with a little time and effort, would that mean that If I ripped an arc at at this voltage I would be making antimatter?
what exactly IS the relationship between this voltage and Particles?
in Real terms please!
Posted 19 January 2008 - 05:48 PM
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Posted 19 January 2008 - 06:17 PM
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Posted 19 January 2008 - 06:28 PM
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Posted 19 January 2008 - 06:53 PM
Posted 19 January 2008 - 08:33 PM
The potential difference is large enough but an electron set free will be acelerated over a short distance before it hits an air molecule. It won't get to cover the whole distance from 1.1MV to ground so it won't get that much energy.
You would need to put the voltage across a vacuum tube to get a high enough energy to generate antimatter. Even then you would need to get the right sort of collision to get antimatter.
Posted 20 January 2008 - 04:00 AM
Think of eV as E as in E=mc^2:
the mass of an electron is appx. 9.109E-31 kg, therefore:
E=(9.109E-31 kg)(3E8 m/s^2)=8.1981E-14 kg.m^2/s^2 = 8.1981e-14 N (or J).
Since 1eV = 1.602E-19 J, 9.1981E-14 J/ 1.602E-19 eV/J = 511741.57 eV
0.511...MeV. (a proton is appx. 938 MeV)
When a photon meets or exceeds an energy of ~1.022 MeV, it is in the range where pair production may occur. When this happens, the photon converts into an electron:positron pair. These annihilate to yield two photons of 0.511 MeV, which are emitted at 180°, relative to one another.
This phenomena is readily observed with gamma spectrum analysis of 60Co.
This is an amazing proof to see in the lab. Mass and energy are perfectly conserved and convertable *drools*.
This is almost as cool as seeing a muon take minutes to decay when at near relativistic velocities.
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