how do you calculate the amount of force the electric field departs onto the charge after it has been released from its static position

 

math welcome

[math]F=\frac{kq1q2}{d^2}[/math]

 

right?

so say you got 10 micro couloms to the right of a -2 micro couloms test charge.

 

is this what you are getting at?

no thats coulombs law,

 

Im getting at trying to calculate force from a potential.

 

the potential energy of a system is the amount of energy required to assemble the system. its easy eneough to calculate through integration but, thats only when the system is static. when the particle moves between to points its also possible to calculate how much energy is departed onto the particle between those tow points which is the particles momentum. however I want to know how much force is applied.

F = qE

oh.......yeah what he said.

but what f you only have the potential V between to particles at r distance from eachother and then they are released how much force would they recieve

divide the potential by the distance.

so

 

F=V/r

 

however which distance is that the distance between the to particles or the distance that they traveled after beng released?

is that the same as

 

[math]|E|=\frac{V}{d}[/math]