hoola Posted February 9, 2015 Share Posted February 9, 2015 (edited) I was watching Suskind (string theory and M theory, lesson one) describing a Feynman diagram of the collision of two pi mesons into a Rowe meson, then a quick decay back into two pi mesons. Then he described a single pi meson changing into a Rowe meson with another quick return to the single pi meson. He went on further to explain the math describing the second reaction was not a lower-equivalent of the first to the degree one would have expected. If this is a correct interpretation of the lesson, does that indicate the 2 pi mesons of the first experiment merge and become a single "double" Rowe meson? How does this square with the uncertainly principle against two particles in the same space? Edited February 9, 2015 by hoola Link to comment Share on other sites More sharing options...
Mordred Posted February 9, 2015 Share Posted February 9, 2015 Becomes a single rho meson. Mesons have integer spin, they are bosonic and bosons do not follow the Pauli exclusion principle. Any number of bosons can occupy the same space. Link to comment Share on other sites More sharing options...
hoola Posted February 9, 2015 Author Share Posted February 9, 2015 thank you mordred. Link to comment Share on other sites More sharing options...
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