Externet Posted March 26, 2013 Share Posted March 26, 2013 In this formula: ============================================= The total power radiated by a ground dipole is where f is the frequency I is the RMS current in the loop L is the length of the transmission line c is the speed of light h is the height above ground of the ionosphere D layer σ is the ground conductivity ============================================ The smaller the factor σ ---> the larger the power. ------> Does it mean reducing conductivity (or increasing resistivity) increases power ? Is that correct ? [ From http://en.wikipedia.org/wiki/Ground_antenna ] Link to comment Share on other sites More sharing options...

elfmotat Posted March 26, 2013 Share Posted March 26, 2013 The basic laws of currents tell us that the power dissipated by a resistor is [math]P=I^2 R[/math]. Resistivity [math]\rho[/math], which is proportional to resistance, is related to conductivity [math]\sigma[/math] by the equation [math]\rho \sigma =1[/math]. So yes, that equation looks right to me. Link to comment Share on other sites More sharing options...

derek w Posted March 26, 2013 Share Posted March 26, 2013 A change in conductivity or resistance,changes the output not the input. Link to comment Share on other sites More sharing options...

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