Semjase Posted September 13, 2012 Share Posted September 13, 2012 The Semjase equation for pi ln(.5-.75^.5)= -a+i*pi Anyone care to prove or disprove? Link to comment Share on other sites More sharing options...
Fuzzwood Posted September 13, 2012 Share Posted September 13, 2012 ln of a negative number is not defined. Link to comment Share on other sites More sharing options...
mathematic Posted September 13, 2012 Share Posted September 13, 2012 (edited) π = -2iln(i) so what! Edited September 13, 2012 by mathematic Link to comment Share on other sites More sharing options...
Bignose Posted September 14, 2012 Share Posted September 14, 2012 (edited) This really isn't anything too profound. The extension of the natural logarithm to the negative numbers is commonly expressed as [math]Log(z) = \ln® + i\theta[/math] where [math]z=r\exp(i\theta)[/math]. For a real negative number, [math]\theta = -\pi[/math]. So, all you did was shove a fairly weird negative number in there. To be exceptionally pedantic, the natural logarithm isn't defined on anything but the positive reals. Usually, this extension is called the complex logarithm function, and hence the slightly different symbol 'Log' used above. more here: http://en.wikipedia.org/wiki/Complex_logarithm Edited September 14, 2012 by Bignose 1 Link to comment Share on other sites More sharing options...
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