The Semjase equation for pi

 

 

 

 

ln(.5-.75^.5)= -a+i*pi

 

 

Anyone care to prove or disprove?

ln of a negative number is not defined.

π = -2iln(i) so what!

Edited September 13, 201213 yr by mathematic

This really isn't anything too profound. The extension of the natural logarithm to the negative numbers is commonly expressed as

 

[math]Log(z) = \ln® + i\theta[/math] where [math]z=r\exp(i\theta)[/math].

 

For a real negative number, [math]\theta = -\pi[/math].

 

So, all you did was shove a fairly weird negative number in there.

 

To be exceptionally pedantic, the natural logarithm isn't defined on anything but the positive reals. Usually, this extension is called the complex logarithm function, and hence the slightly different symbol 'Log' used above.

 

more here: http://en.wikipedia.org/wiki/Complex_logarithm

Edited September 14, 201213 yr by Bignose