Time And Space Posted January 16, 2013 Share Posted January 16, 2013 0/0 = Set of All Numbers The Value of 0/0 depends upon from where it has come like (x^{2}-9)/(x-3)=0/0 if x=3 but if x->3 then (x^{2}-9)/(x-3)=6 so in this case 0/0=6 Link to comment Share on other sites More sharing options...

NaxAlpha Posted January 29, 2013 Share Posted January 29, 2013 You can solve these problems your-self ==>what will be velocity when object trevells 0 m distance in 0 seconds ==>what will be acceleration when delta velocity=0 and t=0 ==>You did zero work in no time what will be your Power As a matter of fact some mathematical problems are not applicable in physics ==>Answer to 0/0 is mostly applicable in calculus like this (x^2-9)/(x-3) becomes 0/0 when x=0 but if we take x->0 then this becomes 6 that's mean that 0/0 is 6 in this case Link to comment Share on other sites More sharing options...

Bignose Posted January 29, 2013 Share Posted January 29, 2013 You can solve these problems your-self ==>what will be velocity when object trevells 0 m distance in 0 seconds ==>what will be acceleration when delta velocity=0 and t=0 ==>You did zero work in no time what will be your Power No, your velocity is undefined. 0 m in 0 seconds is not defined. See all the reasons listed in the thread above. With an undefined velocity, it makes no sense to talk about concepts like acceleration or power. 1 Link to comment Share on other sites More sharing options...

Orion1 Posted January 31, 2013 Share Posted January 31, 2013 (edited) Consider the mirrored functions: [math]f_1(x) = (x - dx)^2 + dy[/math] [math]f_2(x) = -(x - dx)^2 + dy[/math] And: [math]f_3(x) = \frac{f_2(x)}{f_1(x)} \; \; \; \; \; \; f_1(x) \neq 0[/math] Where [math]dx[/math] and [math]dy[/math] are x-axis and y-axis differential shifts. Note that if [math]dy = 0[/math], an indeterminate expression of [math]\frac{0}{0}[/math] occurs in function [math]f_3(x)[/math], as indicated by a flat line in graph02. However, if [math]dy \neq 0[/math] and exists as an infinitesimal, the indeterminate expression is resolved for all values of [math]x[/math] and [math]dx[/math], as indicated in exaggeration in graph03 and graph04. Graph plots and differential shifts: graph01 - [math]f_1(x),f_2(x), dx = 0, dy = 0[/math] graph02 - [math]f_3(x), dx = 0, dy = 0[/math] graph03 - [math]f_1(x),f_2(x), dx = 0, dy = 1[/math] graph04 - [math]f_3(x), dx = 0, dy = 1[/math] graph01.bmp graph02.bmp graph03.bmp graph04.bmp Edited January 31, 2013 by Orion1 Link to comment Share on other sites More sharing options...

ahmetsinav Posted February 20, 2013 Share Posted February 20, 2013 This is something I posted in an earlier thread:="f you calculate (8-x^3)/(2-x) when x=2 you get 0/0........................... I'll just say I make this example of 0/0 equal to 12........................" Link to comment Share on other sites More sharing options...

Amaton Posted February 21, 2013 Share Posted February 21, 2013 (edited) If there's a 0/0 in a function, I don't think we can simply equate 0/0 with an existing limit at that point. Consider a function [math]f(x)=\frac{g(x)}{h(x)}[/math], where [math]g(x)[/math] and [math]h(x)[/math] are non-constant differentiable functions. If there exists a constant [math]a[/math] such that [math]f(a)[/math] results in [math]\frac{0}{0}[/math], is [math]f(a)[/math] not always undefined? Regardless of any limit that may exist? Edited February 21, 2013 by Amaton Link to comment Share on other sites More sharing options...

SamBridge Posted February 24, 2013 Share Posted February 24, 2013 (edited) If you look at the algebraic equivalent of [math]\frac{0}{0} = x [/math] it's [math]x\times0 = 0 [/math]. In this case, x can literally be any number since anything times 0 is 0. This is why I think the answer is appropriately called "undefined". You can literally put "0" into something any amount of times you want, the derivative of the vertex of absolute value(x) could literally be anything within the parameters of 360 inus the interior angle , literally any number times 0 could equal 0. It seems to make sense that it is "undefined" because there is nothing in mathematics forcing the result to be any particular number. Edited February 24, 2013 by SamBridge Link to comment Share on other sites More sharing options...

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