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a twist on standard model


derek w

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If we take the standard model and twist it around slightly and state it as follows:-

 

Energy is positively charged (+)

anti-energy is negatively charged (-)

 

Energy creates matter (positive)

anti-energy creates anti-matter (negative)

 

m+ matter a- anti-matter

 

 

up quark consists by ratio of (m+ a- m+) = (+2 -1)

down quark consists by ratio of (a- m+ a-) = (-2 +1)

 

 

proton consists of (up up down) = 2(+2 -1) + (-2 +1) = +5 -4

anti proton consists of (down down up) = 2(-2 +1) + (+2 -1) -5 +4

 

 

electron = a-

positron = m+

 

 

neutron = proton + electron

anti-neutron = anti-proton + positron

 

 

hydrogen atom = proton + electron = 2(+2 -1) + (+1 -2) + (-1) = zero

anti hydrogen atom = anti-proton + positron = 2(-2 +1) + (+2 -1) + (+1) = zero

 

 

If nothing else,I can say that this model obeys conservation of energy law(energy in + energy out =zero)

My question is can it be applied,or am I missing some factor?

Edited by derek w
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neutron = proton + electron

anti-neutron = anti-proton + positron

My question is can it be applied,or am I missing some factor?

 

You have violated conservation of lepton number. You need a neutrino or antineutrino, depending on which side of the equation it gets placed.

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Thanks for the feedback.If in this model the electron is made of anti-matter.Then i would say:-

 

neutron = proton + electron + anti-electron neutrino

anti-neutron = anti-proton + positron + positron neutrino

 

 

I think I would have to add a definition to this:-

 

anti-electron neutrino = kinetic anti-energy (negative)

positron neutrino = kinetic energy (positive)

Edited by derek w
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Answer to both questions I do not know.I am thinking in terms of a puzzle.But it predicts where all the anti-matter has gone.I can but explore the idea further until I can go no further.

Edited by derek w
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Having thought about this model,an idea has occurred to me.If I multiple my units by 3 as follows:-

 

 

Up quark = (5m+ 4a-)

down quark = (5a- 4m+)

 

 

proton = spherical rubik's cube(up up down) = (14m+ 13a-) = m+

 

(m+ a- m+) (a- m+ a-) (m+ a- M+)

(a- m+ a-) (m+ a- m+) (a- m+ a-)

(m+ a- m+) (a- m+ a-) (m+ a- m+)

 

up down up

 

A spherical rubik's cube with the (a-) at centre of down quark at centre of spherical rubik's cube.The sphere would have to spin at high revs creating enough angular momentum to equal force of attraction.this would increase mass of proton in comparison to the sum of the individual quarks.

 

photon would consist of equal ratio of energy (m+ a-)

 

I would have to add the value (q) to this model:-

q = a number greater than 1 but less than infinity.

 

then say that m+ = q x m+/q

and that a- = q x a-/q

 

For example if I put in that q = 10^9 then:-

 

m+ = 10^9 x m+/10^9

a- = 10^9 x a-/10^9

Edited by derek w
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If we take standard model and twist it around slightly,and state it as follows:-

 

energy is positively charged (+)

anti-energy is negatively charged (-)

 

energy creates matter (m+)

anti-energy creates anti-matter (a-)

 

by ratio of (m+) and (a-) particles consist as follows:-

 

 

electron = 1(a-)

positron = 1(m+)

 

up quark = 1(m+) + 2/6(a-).....................charge = +2/3

down quark = 5/6(a-) + 3/6(m+)...........charge = -1/3

anti-up quark = 1(a-) + 2/6(m+)..............charge = -2/3

anti-down quark = 5/6(m+) + 3/6(a-)....charge = +1/3

 

delta baryons:-

 

(uuu) = 3(m+) & 1(a-)..............charge = +2

(uud) = 2.5(m+) & 1.5(a-).........charge = +1

(udd) = 2(m+) & 2(a-)............charge = 0

(ddd) = 2.5(a-) & 1.5(m+)........charge = -1

 

 

hydrogen atom = proton 2.5(m+) + 1.5(a-) + electron 1(a-) = charge 0

 

 

anti delta baryons

 

(-u-u-u) = 3(a-) & 1(m+)...........charge = -2

(-u-u-d) = 2.5(a-) & 1.5(m+).........charge = -1

(-u-d-d) = 2(a-) & 2(m+)...........charge = 0

(-d-d-d) = 2.5(m+) & 1.5(a-).........charge = +1

 

 

anti-hydrogen atom = anti-proton 2.5(a-) + 1.5(m+) + positron 1(m+) = charge 0

 

 

 

 

 

Edited by derek w
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