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Simple. But think it again.


alpha2cen

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You should try to write in complete sentences. Also, you should make your point clear rather than posting "a chicken crosses the road. think about it!". Expecting people to invest time into your thoughts and at the same time putting less than five minutes of effort into it yourself is just rude.

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You should try to write in complete sentences. Also, you should make your point clear rather than posting "a chicken crosses the road. think about it!". Expecting people to invest time into your thoughts and at the same time putting less than five minutes of effort into it yourself is just rude.

 

Do you know the hidden something?

Its important but we don't know.

So forum is important.

Every one could answer like this.

3 ball/2 =1.5 ball

3 cup of water/2 = 1.5 cup of water

But it has some fault.

I'll give next post tomorrow.

Edited by alpha2cen
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Do you know the hidden something?

Its important but we don't know.

So forum is important.

Every one could answer like this.

3 ball/2 =1.5 ball

3 cup of water/2 = 1.5 cup of water

But it has some fault.

I'll give next post tomorrow.

The fault: you incorrectly increase the number of significant figures.

Edited by CaptainPanic
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The fault: you incorrectly increase the number of significant figures.

 

How about this solution?

1)

3 ball/2=?

transform to dimensionless form

= 3a /2, a[ball/ball]

calculation

= 1.5 a

transform to dimension form

= 1 ball + 1 part of teared ball

2)

3 cup of water /2=?

transform to dimensionless form

=3b/2, b[cup of water/cup of water]

calculation

=1.5b

transform to dimension form

= 1.5 cup of water

When it is divided., water can not be changed it's original property.

The unit , cup is not a measured value(cm, sec, ...).

So the number of significant figure is not no problem.

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  • 1 month later...

This problem is not a normal mathematical division, it's an integer division:

 

let's assume that A is number of divided Objects, and B is number of members

 

1. using Integer division:

X = A div B

Y = A mod B

if X = 1 then objects divided success, else failure

if Y > 0 then Y objects remain after division

if Y = A then division failed

 

2. using recurrence definition:

S = { 0, 0, 0, ... }, S represent what every member owns

-------------

a. IF [ B < 1 ] OR [ A < 1 ] THEN STOP

b. z = A mod cut, where cut is number of objects meant for every member

c. A = A - z

d. Sb = z

e. B = B - 1

f. GOTO STEP a

-------------

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This concept is some different.

The main point what I state is the difference between arithmetic calculation and real life calculation.

Arithmetic calculation should be done by using nondimensional number.

If not, the result gives us some confusion.

So good problem solving procedure is like this.

make equation--->transfer dimensionless form --------> calculation ------>transfer dimension form----->result

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This concept is some different.

The main point what I state is the difference between arithmetic calculation and real life calculation.

Arithmetic calculation should be done by using nondimensional number.

If not, the result gives us some confusion.

So good problem solving procedure is like this.

make equation--->transfer dimensionless form --------> calculation ------>transfer dimension form----->result

 

I didn't bring anything from my brain, this problem is well-known and already have solutions ...

 

Look up Binary Knapsack Problem HERE

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  • 2 weeks later...

But 1 cup does not have exact value.

For example other units

1m=100cm

1kg=1000g

and measured value is like this.

1.005m

1.00006kg

But we generally do not use 0.23cup.

 

YOU don't. But people do.

Again, one metric cup=250ml Exactly. Which makes it an "exact value".

2 cups=500ml

0.23 cups=57.5ml

Edited by Gozonji
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