Gamewizard Posted March 23, 2010 Share Posted March 23, 2010 Hi, i have another question which i need help with. Bacteriophage DNA is 48000 base pairs long. Hae III cuts it into 206 peices. Hind III cuts it in 7 places, whilst another 6-cutter Pst I cuts it into 28 peices. Why the diffrence? I am thinking is this because they are specific ? as in 6-cutter, 4-cutter etc? or is it something to do with DNA sequences? Link to comment Share on other sites More sharing options...
ecoli Posted March 23, 2010 Share Posted March 23, 2010 Restriction enzymes cut at a specific DNA sequence. Link to comment Share on other sites More sharing options...
CharonY Posted March 23, 2010 Share Posted March 23, 2010 Technically only type II restriction enzymes (as the one mentioned in the OP) cut at specific sites. But in direct to the question, yes it is because of the fact that the recognition length differs. A 4bp recognition sequence is likely to be more abundant in any given sequence than a 6 bp sequence. Unless of course that for some reason the sequence is devoid of any recognition sites (which is often the case in artificial DNA molecules). But in any random fragment the amount of potential sites scales inversely with the length of the recognition sequence. Link to comment Share on other sites More sharing options...
Gamewizard Posted March 24, 2010 Author Share Posted March 24, 2010 Thank you i am sure about this now. Link to comment Share on other sites More sharing options...
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