Gareth56 Posted November 5, 2008 Share Posted November 5, 2008 Continuing through the algebra book I'm studying I came across this example but cannot decide if it's correct or not. Sorry but I just cannot get to grips with the proper way to present this type of equation on this forum. Hopefully it'll make sense. x^2 y^3 3z^-4 = x^2y^3z^4[/u] 3 Sorry i can't get the 3 directly underneath = x^2y^3z^4 Doesn't it work out that the 3 also comes up to the numerator? Or is it only the z^-4 that comes up if so why does the 3 stay below? Link to comment Share on other sites More sharing options...
Cap'n Refsmmat Posted November 5, 2008 Share Posted November 5, 2008 (edited) [math]\frac{x^2y^3}{3z^{-4}} = \frac{x^2y^3z^4}{3}[/math] So yes, you're right. Only the [imath]z^{-4}[/imath] moves up. Remember that [imath]3z^{-4}[/imath] is the same as [imath]3 \times z^{-4}[/imath] -- the negative exponent only applies to [imath]z[/imath], not the 3. Edited November 5, 2008 by Cap'n Refsmmat oops -- LaTeX trouble 1 Link to comment Share on other sites More sharing options...
Gareth56 Posted November 5, 2008 Author Share Posted November 5, 2008 Many thanks for the clarification. Both of you Link to comment Share on other sites More sharing options...
DrP Posted November 5, 2008 Share Posted November 5, 2008 (edited) The 3 would come up if there were brackets around the 3z. i.e. [3z]^-4 meaning the 3 and the z are to the power of -4. But the way you have it the 3 stays on the bottom. i.e. 3z^-4 means that the z only is raised to the power of -4 and the 3 is just what it is. EDIT: Whoops - sorry - you beat me to it. Edited November 5, 2008 by DrP 1 Link to comment Share on other sites More sharing options...
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