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Calculation of mirror mass using sun gravitational lens formula

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Calculation of mirror mass from light radiation pressure force and gravitational force acting on mirror inside the sun gravitational lens

The formula for angle of bent light inside the sun gravitational lens.



a=4GM/C^2xr



r= 69.7x10^8m this is the distance from center of sun to mirror.Two forces are acting on mirror:
Pressure radiation force from light reflected from Jupiter surface and gravitational force of Sun.

The formula for angle of bent light is



a=4GM/C^2xr



r= 69.7x10^8m this is the distance from center of sun to mirror





Mirror has area A=1 m^2



m=? mass of mirror is not known



a=4x6.6x10^-11 x 1.9x10^30/9x10^18x69.7x10^8



a=7.9x10^-7







The intensity of radiation of light reflected from Jupiter is

I=1.8w/m2



The radiation pressure acting on surface of mirror is



P=I/C=1.8/3x10^8=0.6x10^-8



The force acting on mirror is

Frp =6x10^-9N



IMG_5480.png



The gravitational force pulling on the mirror is



Fg=Frp x tan a



And



Fg=m x g



tan a=1.37x10^-9





Fg=1.37x10^-9x 6x10^-9



Fg=8.22x10^-18N



The gravitational acceleration of Sun



g=GM/r^2



g=6.6x10^-11 x 1.9x10^30/4.8x10^19



g=2.69m/s





mass of mirror



m=Fg/g



m=8.2x10^-18/2.67



m‎ = 3.0712×10⁻¹⁸kg

IMG_5531.png





The length of curvature of light path is

L=tg a x r



L=1.37x10^-9x69.7x10^8



L‎ = 9.549m



Work made by resultant force is



Ft x L=E- work



Ft^2=Frp^2 + Fg^2



Ft=Frp





E=6x10^-9x9.54



E= 5.7x10^-8J



E=mx v^2/2



V^2=5.7x10^-8/3x10^-18



V^2=1.9x10^10

V=1.37x10^5m/s





To confirm:



Centrifugal force



Fc=m x v^2/r



Fc=3x10^-18x1.86x10^10/69.7x10^8



Fc=0.08x10^18



(Fg=8.2x10^-18)********



The mirror is “pushed” in straight line by radiation pressure force - crated by reflected light from surface of Jupiter and “pulled” towards the sun by sun gravitational force.
The angle of sun gravitational lens(angle) formula is used to calculate mass .

Opinions ?

You haven’t explained enough about how all this is allegedly connected (How are these things connected> what does Jupiter have to do with this?)

It looks to me like you just threw a bunch of equations up there that are only loosely related but have no obvious significance to the very-poorly-defined example. It’s word salad with some math croutons

  • Author

The Jupiter is very well known and data about Jupiter is easily found .

The mirror traveling for 9.5m will mimic the trajectory of light beam being bent .

The massless deflected light wave coming from Jupiter has area of 1 m^2(square 1mx1m) is going to be bent for angle a(10^-5 degrees ) for a distance
Of 9.5m
The Sun is curving time space and this curvature of time space is bending light .
The mirror traveling inside this Jupiter wave is been pushed “horizontally “by radiation pressure force
And “pulled “ down by gravitational force - the trajectory of mirror is identical to trajectory of light wave .
The mirror has mass and curvature of space time caused by gravitation of sun is not enough to mimic curved trajectory.
It takes horizontal force (Jupiter light radiation pressure force ) and curvature of time space (gravitational force) to mimic curved trajectory of massless wave .

Sun gravitational lensing is curving the space time and bending the light (massless wave )in 95 m distance .

Compared to:

The same space time curvature is mimicked by using two Newtonian forces acting on mirror (baryonic matter with mass).

The first force is explained as massless wave transferring momentum to the surface .
The second force is explained as a curvature of space time .







13 hours ago, jv1 said:

The Jupiter is very well known and data about Jupiter is easily found .

Then it should be no problem to link to it.

13 hours ago, jv1 said:

The mirror traveling for 9.5m will mimic the trajectory of light beam being bent .

Where is this mirror and what is the significance of 9.5m?

13 hours ago, jv1 said:


The massless deflected light wave coming from Jupiter has area of 1 m^2(square 1mx1m) is going to be bent for angle a(10^-5 degrees ) for a distance
Of 9.5m

The angle depends on where the mirror is, and, again, the significance of 9.5m is not explained.

13 hours ago, jv1 said:


The Sun is curving time space and this curvature of time space is bending light .
The mirror traveling inside this Jupiter wave is been pushed “horizontally “by radiation pressure force
And “pulled “ down by gravitational force -

“Down” is not defined, and there is radiation pressure and gravity from both the sun and Jupiter

13 hours ago, jv1 said:

the trajectory of mirror is identical to trajectory of light wave .

That’s not obvious; light rarely takes the same trajectory as massive objects unless you’ve got a carefully crafted scenario.

13 hours ago, jv1 said:

The mirror has mass and curvature of space time caused by gravitation of sun is not enough to mimic curved trajectory.
It takes horizontal force (Jupiter light radiation pressure force ) and curvature of time space (gravitational force) to mimic curved trajectory of massless wave .

Horizontal is not defined here

13 hours ago, jv1 said:

Sun gravitational lensing is curving the space time and bending the light (massless wave )in 95 m distance .

95 or the mysterious 9.5?

13 hours ago, jv1 said:

Compared to:

The same space time curvature is mimicked by using two Newtonian forces acting on mirror (baryonic matter with mass).

What two Newtonian forces?

You might have this problem set up in your mind, but you’re not conveying all of the information needed for it to make sense.

  • Author

The distance 0.4AU(69x10^8m) is the closest distance to the sun achieved by satellite.

Satellite is positioned on 12:00 o’clock position on the first picture above .(distance b).

The mirror is positioned between satellite and sun .

The signal from Jupiter comes from “left hand side “perpendicular to the sun /satellite axis.

That is marked source on the posture above.

The mirror falls of of satellite and only for 9.5m(or 3x10^-5s)travels in curved trajectory mimicking the trajectory of light from Jupiter in that same spot(when mirror is not there ).

In this time/distance radiation pressure from sun hits the bottom start of mirror which is A1=1x10^-21m^2)

The intensity of sun radiation is about 8500w/m2

The Sun radiation pressure force acting on the bottom of mirror will be in magnitude of 10^-26N

This force is not going to affect the gravitational pull on mirror(10^-18N).

After 9.5 meter the mirror will be blown away and travel with solar wind away from satellite.

The light from Jupiter will continue to travel to observer at 550AU.

About 9.5 m:

The “chunk “ of curved time space has dimensions 1x1x9.5m.

It is the volume where light bending is happening .

The mirror is pushed for 9.5 m horizontally by Jupiter radiation pressure force .

The gravity is pulling mirror “down” towards the sun .

The mass of mirror is calculated to make trajectories of mirror and bent light signal from Jupiter identical.

The reflected Jupiter light hits 9.5m x1 m area on the top of volume at Alfa (10^-5 degrees ) and acts on curved time space” hard surface” exchange momentum - creating mechanical (Newtonian force)

And gets “pushed down”towards the sun .

We see this motion as a consequence of gravitational force Fg (10^-18N) .

That is force created as a component of radiation pressure force F rp(10^-8)in the text above .

Lower 9.5 x1 m area of volume is bent downwards for the same angle Alfa(a) and deflected light continue to travel towards observer .(at 550Au)

Momentum transfer between massless wave and

Unknown time space curvature - that

is mechanical push of force (radiation pressure force) exerted on the wall(curved time space )-

is this description of mechanical force ?

I read this thread and burst out laughing. There's a sort of Spinal Tap quality to it.

Jupiter absorbs and re-emits light from the Sun (which has nothing to do with Jupiter mass). What you should get familiar with is Albedo. https://en.wikipedia.org/wiki/Albedo

Jupiter emits (in the invisible region of the spectrum) IR, which depends on the internal Jupiter temperature.

The brightness and energy emitted by the Sun (or any other star) does not only depend on its mass, but on the stage of life it is currently in. Currently, the Sun emits 1370 W/m^2 from a distance of 150 million kilometers, which is detectable on Earth. But at a later stage of life, in a few billion years, it will lose mass and emit more energy (which will cause the entire star to grow - its radius will become larger than it is now).

https://en.wikipedia.org/wiki/Red_giant

Why would you count the mass of a mirror? Isn't it simpler to multiply its density by its volume? and calculate the volume using the mirror's radius and inset (curvature) ?

Edited by Sensei

2 hours ago, jv1 said:

The Sun radiation pressure force acting on the bottom of mirror will be in magnitude of 10^-26N

This force is not going to affect the gravitational pull on mirror(10^-18N).

You said you don’t know the mass of the mirror, so how do you know the force?

2 hours ago, jv1 said:

After 9.5 meter the mirror will be blown away and travel with solar wind away from satellite.

The gravitational force is 8 orders of magnitude bigger than the radiation pressure, according to you. How does it blow the mirror away?

On 7/14/2025 at 3:13 PM, jv1 said:

The intensity of radiation of light reflected from Jupiter is

I=1.8w/m2

The radiation pressure acting on surface of mirror is

P=I/C=1.8/3x10^8=0.6x10^-8

The force acting on mirror is

Frp =6x10^-9N

The radiation intensity from Jupiter is several thousand times smaller than that from the sun (according to your numbers) yet you say it exerts a much, much larger force.

  • Author

Let’s try this approach:

The air duct is 1x1 m and 100 meter long .

When straight air ,fluid and light travels through in straight line unchanged .

If the air duct is straight for 90.5 m and than 9.5 meters at the and is bent - air,fluid and light will change direction .

The sun gravitational lensing is “bent” part of time space “duct”.

Anything traveling inside the “duct” or curved space time will change trayectory and follow the shape of “duct “.

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